Issue running a java program from a batch script

Question

I have a problem with a batch script that runs a java program, here some key lines of the script:

exeFinder="java -client -classpath './classes:./lib/javacsv.jar' -Xmx7200m Finder.Main ";
runFinder() {
    cleanFolders;
    $exeFinder $1 $2 $3 > $4;
}
dbName=$1;
k=$2;
n=$3;
outFile="simple_tester-out.log";

runFinder $dbName $k $n $outFile;

I run the script with its arguments: ./myScript.sh testing_7x8.csv 7 8
And I get this:

Error: Could not find or load main class Finder.Main

It looks like a java problem, so I change the line $exeFinder $1 $2 $3 > $4; for echo "$exeFinder $1 $2 $3 > $4"; to get my execution line:

java -client -classpath './classes:./lib/javacsv.jar' -Xmx7200m Finder.Main  testing_7x8.csv 7 8 > simple_tester-out.log

And it works like a charm! So I don't know what is happening.

I have checked some questions like this and this, but I can't see anything useful for me.

Thanks for your time, guys

sounds like a working directory vs classpath issue to me. whats the working directory the java process is run in? given that wd, are "./classes" and "./lib/javacsv.jar" valid paths? — radai
– radai, Commented Mar 9, 2016 at 19:42
yes, they are valid, I'm using the same directory for run the script and for run the "direct way" typing java - client -clas..... directly on the terminal. and the last form works fine. BTW, I have found the problem, or at least a solution. — onlycparra
– onlycparra, Commented Mar 9, 2016 at 20:30

onlycparra · Accepted Answer · 2016-03-09 19:47:40Z

1

It was a little problem with the simple quotes in the execution variable, so instead of:

"java -client -classpath './classes:./lib/javacsv.jar' -Xmx7200m Finder.Main "

it must be:

"java -client -classpath ./classes:./lib/javacsv.jar -Xmx7200m Finder.Main "

It is probably something related with bash and how it works, I don't know enough to explain why this happens, but that change solved the problem.

answered Mar 9, 2016 at 19:47

onlycparra

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Comments

Sam Jones · Accepted Answer · 2016-03-09 19:40:57Z

0

Try sh $exeFinder $1 $2 $3 > $4;

In my testing, I was unable to directly execute a command in a variable, but I could pass it to sh.

answered Mar 9, 2016 at 19:40

Sam Jones

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2 Comments

onlycparra Over a year ago

this didn't work for me, please notice that $exeFinder is a variable that starts with java -client..... so it is like type in the console sh java -classpath.... which make no sense to the console, in fact, it returns sh: 0: Can't open java

Sam Jones Over a year ago

Ah, yeah, that makes sense. I only got as far as testing running a basic command (cd ..) from a variable, and assumed that was the problem when it didn't work for me (and running via sh $variable did). Glad you did find the answer :-)

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