Python Lists: .lower() attribute error

Question

I am trying to create a program on python to do with manipulating lists/arrays. I am having trouble with an error:

lowercase = names.lower
AttributeError: 'list' object has no attribute 'lower'

I really need some help to fix this!

names = [] #Declares an array
print("Type menu(), to begin")
def menu():

    print("----------------------------MENU-----------------------------")
    print("Type: main() for core functions")
    print("Type: delete() to delete a name")
    print("Type: save() to save the code")
    print("Type: load() to load the saved array")
    print("Type: lower() to make all items in the list lower case")
    print("-------------------------------------------------------------")

def main():
    times = int(input("How many names do you want in the array? ")) #Asks the user how many names they want in the array
for i in range(times):
    names.append(input("Enter a name ")) #Creates a for loop that runs for the amount of times the user requested, it asks the user to enter the names
choice = input("Would you like the array printed backwards? ") #asks the user whether they want the array backwards
if choice == "Yes":
    names.reverse() #If the user says yes, the array is reversed then printed backwards
    print(names)
else:
    print(names) #Otherwise, the array is printed normally
number = int(input("Which item would you like to print out? "))
number = number - 1
print(names[number])
start = int(input("What is the first position of the range of items to print out? "))
start = start - 1
end = int(input("What is the last position of the range of items to print out? "))
print(names[start:end])

def delete():
    takeAway = input("Which name would you like to remove? ")
    names.remove(takeAway)
    print(names)

def save():
    saving1 = open("Save.txt", 'w')
    ifsave = input("Would you like to save the array? ")
    if ifsave == "Yes":
        for name in names:
                saving1.write("%s\n" % name)
                saving1.close
    else:
        menu()
def load():
    loadquestion = input("Would you like to load a list of names? ")
    if loadquestion == "Yes":
        saving1 = open('Save.txt', 'r')
        print(saving1.read())
        saving1.close()
    else:
        menu()
def lower():
    lowerq = input("Would you like to make the array lowercase? ")
    if lowerq == "Yes":
        lowercase = names.lower
        print(lowercase)
    else:
        menu()

Please learn to provide a minimal reproducible example, instead of dumping all your code here. — Sнаđошƒаӽ
– Sнаđошƒаӽ, Commented Mar 9, 2016 at 18:23

sytech · Accepted Answer · 2016-03-09 18:38:38Z

3

The variable names is a list. You can't use the .lower() method on a list.

pp_ provided the solution:

lowercase = [x.lower() for x in names]

While not exactly equivalent to the previous example, this may read better to you and has, effectively, the same result:

lowercase=[]
for name in names:
    lowercase.append(name.lower())

Alternate solution that may fit your needs:

print (str(names).lower())

answered Mar 9, 2016 at 18:38

sytech

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Comments

pp_ · Accepted Answer · 2016-03-09 18:27:51Z

2

Like the error message says, you can't use .lower() on lists, only on strings. That means you'll have to iterate over the list and use .lower() on every list item:

lowercase = [x.lower() for x in names]

edited Mar 9, 2016 at 18:27

answered Mar 9, 2016 at 18:22

pp_

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2 Comments

zondo Over a year ago

Another thing to note is that he wasn't actually calling .lower anyway; he was just mentioning it. A second way to do it would be to use map(): lowercase = map(str.lower, names).

n1c9 Over a year ago

also, since this user is obviously new to python, it might be helpful to write out what this list comp actually does: lowercase = [] for x in names: # iterates over list of names lowercase.append(x.lower())

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