C# dynamic ExpandoObject Array

Question

please tell me, how do I get the json like this:

    dynamic packet = new ExpandoObject();
    packet.type = "somethink";
    packet.user = 12345;

    packet.nets[0].amout = 123;
    packet.nets[0].lower = 0;
    packet.nets[1].amout = 345;
    packet.nets[1].lower = 1;
    string input = Newtonsoft.Json.JsonConvert.SerializeObject(packet);

Its not workig, error: An unhandled exception of type "Microsoft.CSharp.RuntimeBinder.RuntimeBinderException" in System.Core.dll

For more information: "System.Dynamic.ExpandoObject" does not contain definitions of "nets"

Thanks.

Matías Fidemraizer · Accepted Answer · 2016-03-10 17:59:56Z

13

It's the ExpandoObject who's a dynamic object. The rest of properties should be other ExpandoObject instances or regular objects, arrays, collections...

For example:

packet.nets = new[] 
{
     new { amount = 123, lower = 0 },
     new { amount = 345, lower = 1 }
}

Or:

packet.nets = new[]
{
     new Dictionary<string, int> { { "amount", 345 }, { "lower", 0 } },
     new Dictionary<string, int> { { "amount", 123 }, { "lower", 1 } }
}

There're many other approaches, including the use of instances of concrete classes.

edited Mar 10, 2016 at 17:59

answered Mar 10, 2016 at 15:57

Matías Fidemraizer

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Comments

Arturo Menchaca · Accepted Answer · 2016-03-10 16:01:52Z

4

Firstly, you need create nets in packet object, like this:

packet.nets = new dynamic[2];

And initialize the objects in nets, if you want with `ExpandoObject too:

packet.nets[0] = new ExpandoObject();
packet.nets[1] = new ExpandoObject();

Then is done, complete code:

dynamic packet = new ExpandoObject();
packet.type = "somethink";
packet.user = 12345;

packet.nets = new dynamic[2];

packet.nets[0] = new ExpandoObject();
packet.nets[0].amout = 123;
packet.nets[0].lower = 0;

packet.nets[1] = new ExpandoObject();
packet.nets[1].amout = 345;
packet.nets[1].lower = 1;            

string input = Newtonsoft.Json.JsonConvert.SerializeObject(packet);

answered Mar 10, 2016 at 16:01

Arturo Menchaca

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Comments

Yuriy Faktorovich · Accepted Answer · 2016-03-10 15:59:24Z

1

You first need to declare nets. For example

packet.nets = new Dictionary<int, dynamic>();

Then you'll need to instantiate the instances of nets

packet.nets[0] = new {amount = 123, lower = 0};

The result being

dynamic packet = new ExpandoObject();
packet.type = "somethink";
packet.user = 12345;

packet.nets = new Dictionary<int, dynamic>();
packet.nets[0] = new { amount = 123, lower = 0 };
packet.nets[1] = new { amount = 345, lower = 1 };

answered Mar 10, 2016 at 15:59

Yuriy Faktorovich

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4 Comments

Matías Fidemraizer Over a year ago

Why the values should be dynamic?

Yuriy Faktorovich Over a year ago

@MatíasFidemraizer I guess they can be object, same difference. Your code automatic array initiation is probably better than declaring it as a Dictionary anyway. The only thing is you can remove the object part, the compiler will assume it. Not sure why you got the downvote, I upvoted.

Matías Fidemraizer Over a year ago

Hey, yeah, I've turned the code to get type inference by usage. In my case I would declare values typed as dynamic if they should be accessed later. If it's just for serialization, who cares, object does the job well too

Matías Fidemraizer Over a year ago

About the downvoter... maybe that user pressed the wrong button or who knows ;P

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