How can I get command line arguments(sys.argv) in python

Question

filename:test.py

import sys
print(sys.version)
print(sys.argv)

I typed python test.py 1 2 3 in the cmd console , it works well.

3.5.1 (v3.5.1:37a07cee5969, Dec  6 2015, 01:54:25) [MSC v.1900 64 bit (AMD64)]
['test.py', '1', '2', '3']

However , I type test.py 1 2 3 in the cmd console, it can only get the first argument.

3.5.0b4 (v3.5.0b4:c0d641054635, Jul 26 2015, 06:55:14) [MSC v.1900 32 bit (Intel)]
['E:\\Bin\\iproc\\test.py']

How can I get these arguments ?

Hm, can't seem to reproduce this. Can you confirm that E:\Bin\iproc\test.py is the right copy of test.py? Is the cmd window finding one in your PATH to run instead? The version of PYthon appears to be different, too, which hints it might a different copy. — Simon Fraser
– Simon Fraser, Commented Mar 11, 2016 at 8:36
python test.py 1 2 3 and import sys print(sys.argv) that's ok tutorialspoint.com/python/python_command_line_arguments.htm — Tim007
– Tim007, Commented Mar 11, 2016 at 8:37
I am sure there is only one copy of test.py in my PATH as I run where test.py,only one test.py is the result. — Lion
– Lion, Commented Mar 11, 2016 at 8:50

cdarke · Accepted Answer · 2016-03-11 09:10:09Z

2

Sounds like your Windows file association is bad. Make sure arguments are passed as %%*. Use the assoc and ftype commands in cmd.exe to check. For example:

ASSOC .py=Python.File
FTYPE Python.File="C:\Python35\python.exe" "%%1" %%*

edited Mar 11, 2016 at 9:10

answered Mar 11, 2016 at 8:50

cdarke

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2 Comments

Lion Over a year ago

It does not work.c:\bin\python35\python.exe: can't open file '%1': [Errno 2] No such file or directory

cdarke Over a year ago

What didn't work? Did you get that error from the ftype command or when you tried to run the python script? What does ftype show?

Lion · Accepted Answer · 2016-03-11 10:27:10Z

1

Yes, my Windows file association is bad.I Checked the registry , and finally changed the registry . The problem is solved .

[HKEY_CLASSES_ROOT\Applications\python.exe\shell\open\command] @="\"c:\\bin\\python35\\python.exe\" \"%L\" %*"

answered Mar 11, 2016 at 10:27

Lion

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