vb.net Array.Find string by Length

Question

i have an array of string like this :

A
B
C
D
E
F

i know how to get the index of one letter in the array string like this

Dim itemindex As String = Array.IndexOf(myarr, "C")
TextBox2.Text = itemindex

It return for me the number 2

but i want to know how to do it in the Reverse way like if i give the index 2 i want it to return for me the letter C ?

i want to do that for tow array withe the same size one in the listbox if i select one item i want it to return for me the item in the second array that have the same index number

i give the index 2 i want it to return for me the letter C would be: Dim find = myArr(2) common ordinary array reference by index. No idea how the length from the title comes into play — Ňɏssa Pøngjǣrdenlarp
– Ňɏssa Pøngjǣrdenlarp, Commented Mar 11, 2016 at 21:32
@Plutonix Dim charc As String = ListBox2.SelectedItem Select Case charc ` Case charc` charc = myarr(ListBox1.SelectedIndex) End Select TextBox1.Text = charc work for me thank you so match !!!! — Snoopy Ohoo
– Snoopy Ohoo, Commented Mar 11, 2016 at 21:40
it looks like listbox.selectedindex would work and without the implicit data type conversion — Ňɏssa Pøngjǣrdenlarp
– Ňɏssa Pøngjǣrdenlarp, Commented Mar 11, 2016 at 21:42

ManoDestra · Accepted Answer · 2016-03-11 21:35:29Z

1

Just use myArr(2) to access the 3rd element in the array.

Or to get a character from a string, use SubString e.g.

s.Substring(startIndex, length)

Length for you would be 1, if you're looking for a single character.

answered Mar 11, 2016 at 21:35

ManoDestra

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