python function .json(): No JSON object could be decoded

Question

the function looks like this:

import requests
import json
def parse(s):
    r = requests.post('http://166.111.139.15:9000/?properties%3d%7b%22annotators%22%3a%22tokenize%2cssplit%2cpos%2clemma%2cparse%22%2c%22outputFormat%22%3a%22json%22%7d%0a', data=s)
    return r.json()

print parse("I am a student")

And when I use it in Django, the web page shows: "No JSON object could be decoded".Why?

Try using return r.content()

ZdaR
– ZdaR

2016-03-12 07:35:06 +00:00
Commented Mar 12, 2016 at 7:35 — ZdaR
– ZdaR, Commented Mar 12, 2016 at 7:35

Zibi · Accepted Answer · 2016-03-12 08:03:16Z

3

No JSON object could be decoded is an exception message raised at r.json(). If your response is not a valid json object you can still retrieve it with r.text. Even if you are sure your response is always a valid json object, you should still check whether server returned a success code. If there's an internal server error (code 500), you won't get a valid json response!

import requests

def parse(s)
    r = requests.post('http://someserver.com', data=s)
    if r.status_code !== 200:
        return "There was a problem: {} !".format(r.text)
    return r.json()

answered Mar 12, 2016 at 8:03

Zibi

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1 Comment

Kos Over a year ago

I like to use r.raise_for_status()

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