How to split string on second character match in python?

Question

I have my string in variable:

query = 'name=Alan age=23, name=Jake age=24'

how do I split my string on name=Jake instead of name=Alan? Don't suggest query.split(name=Alan), it won't work in my case.

I need something that will skip first name and continue searching for second, and then do split. So, how can i do that?

Have you tried splitting on commas and performing lstrip on the remaining string? — Shrey
– Shrey, Commented Mar 13, 2016 at 18:49
I want output to be in this format: name1 = query.split(1) name2 = query.split(2) name3 = .... — EV3REST
– EV3REST, Commented Mar 13, 2016 at 18:52
@EV3REST Can you write a sample output, like an actual string that demonstrates what you're looking for? — Shrey
– Shrey, Commented Mar 13, 2016 at 18:53

Ali Nikneshan · Accepted Answer · 2016-03-13 18:50:06Z

1

Use query.split(',')[1].split('name')

answered Mar 13, 2016 at 18:50

Ali Nikneshan

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Bernardo Meurer · Accepted Answer · 2016-03-13 19:01:45Z

0

You can try splitting on the comma and then on the spaces like so:

query = 'name=Alan age=23, name=Jake age=24'
query_split = [x.strip() for x in query.split(",")]
names = [a.split(" ")[0][5:] for a in query_split]
print(names)

['Alan', 'Jake']

With this you don't need multiple variables since all your names will be in the list names, you can reference them by names[0], names[1] and so on for any given number of names.

edited Mar 13, 2016 at 19:01

answered Mar 13, 2016 at 18:49

Bernardo Meurer

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5 Comments

EV3REST Over a year ago

i have more than 2 'names' in the string, so i need to skip n amount of characters, that's what I was asking.

Bernardo Meurer Over a year ago

@EV3REST Skip until you reach what? What's your expected output?

Bernardo Meurer Over a year ago

@EV3REST There, that should do it.

EV3REST Over a year ago

I need to have different names in different virables, and names count is more than 2

Bernardo Meurer Over a year ago

@EV3REST You don't need different variables and that works for any number of names. names[0] will be Alan, names[1] will be Jake and so on.

Shrey · Accepted Answer · 2016-03-13 19:02:51Z

0

Try this:

query = 'name=Alan age=23, name=Jake age=24'
names = [y.split(" ")[0][5:] for y in (x.strip() for x in query.split(","))]
print(names)

Output:

['Alan', 'Jake']

edited Mar 13, 2016 at 19:02

answered Mar 13, 2016 at 18:51

Shrey

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