ASP.NET MVC pass parameter to controller with argument

Question

I have problem with passing parameter in controller.

I get id value in public ActionResult AddIngridient(int id = 0) and i need to pass it in public ActionResult AddIngridient(Ingredients ingridients) like IngredientID. How to do this?

I have model:

public partial class Ingredients
{
    public int IngredientID { get; set; }
    public Nullable<int> AmountID { get; set; }
    public Nullable<int> IngredientTypeID { get; set; }
}

And controllers:

public ActionResult AddIngridient(int id = 0)
    {
        IEnumerable<Ingredient> ListOfIngridient =  FRE.Ingredient.Select(key => key).ToList();
        ViewBag.IngridientsList = new SelectList(ListOfIngridient,"IngredientID", "IngredientName");

        IEnumerable<Amount> ListOfAmounts = FRE.Amount.Select(key => key).ToList();
        ViewBag.AmountsList = new SelectList(ListOfAmounts, "AmountID", "AmountName");

        ViewBag.ID = id;
        return View();
    }
    [HttpPost]
    public ActionResult AddIngridient(Ingredients ingridients)
    {
        return View();
    }

View looks like:

@model FoodRecipes.Models.Ingredients
@{
ViewBag.Title = "AddIngridient";
}

<h2>AddIngridient</h2>
@using(Html.BeginForm())
{ 
@Html.DropDownListFor(model => model.IngredientTypeID, (SelectList)ViewBag.IngridientsList)
<br />
@Html.DropDownListFor(model => model.AmountID, (SelectList)ViewBag.AmountsList)
 <input type="submit" value="Create" />
}

have you tried to set the action you want to post? like this: @using(Html.BeginForm("AddIngridient","YourControllerName")) — Ricardo Pontual
– Ricardo Pontual, Commented Mar 16, 2016 at 17:06
@RicardoPontual this is only needed when you want to jump to other controller outside the current route. And, absolutely, not represent a problem in the context of this question. — Balde
– Balde, Commented Mar 16, 2016 at 17:15

teo van kot · Accepted Answer · 2016-03-16 17:04:36Z

1

You should use @Html.HiddenFor() helper.

In your case:

@using(Html.BeginForm("AddIngridient","YourControllerName"))
{ 
   @Html.HiddenFor(x => x.IngredientID) //this line 
   @Html.DropDownListFor(model => model.IngredientTypeID, (SelectList)ViewBag.IngridientsList)
   <br />
   @Html.DropDownListFor(model => model.AmountID, (SelectList)ViewBag.AmountsList)
   <input type="submit" value="Create" />
}

It will produce input type hidden with name IngredientID that will be passed to server on form POST.

answered Mar 16, 2016 at 17:04

teo van kot

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3 Comments

A191919 Over a year ago

If ViewBag.ID = id, contain value that need to place in model.IngridientID, maybe it should be something like @Html.HiddenFor(model => ViewBag.ID)

teo van kot Over a year ago

@A191919 no, it' better to set it to ingridientid model property in controller. That's mvc way

Balde Over a year ago

@A191919 The correct helper is: @Html.Hidden("IngedientID", ViewBag.ID). But my answer explains the right way to work with models, considering that you can add more properties to your model, and it is a bad practice to populate ViewBag with properties of the model.

Balde · Accepted Answer · 2016-03-16 17:24:18Z

You should change your code of AddIngredient Action to return the model:

public ActionResult AddIngridient(int id = 0)
{
    IEnumerable<Ingredient> ListOfIngridient =  FRE.Ingredient.Select(key => key).ToList();
    ViewBag.IngridientsList = new SelectList(ListOfIngridient,"IngredientID", "IngredientName");

    IEnumerable<Amount> ListOfAmounts = FRE.Amount.Select(key => key).ToList();
    ViewBag.AmountsList = new SelectList(ListOfAmounts, "AmountID", "AmountName");

    return View(new Ingredients { IngredientID = id });
}

And in your view add a input type hidden:

@using(Html.BeginForm())
{ 
   @Html.HiddenFor(model => model.IngredientID)
   @Html.DropDownListFor(model => model.IngredientTypeID, (SelectList)ViewBag.IngridientsList)
   <br />
   @Html.DropDownListFor(model => model.AmountID, (SelectList)ViewBag.AmountsList)
   <input type="submit" value="Create" />
}

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