Making a Swift Array Statement More Concise

Question

I am a newbie when it comes to programming and just started learning Swift. Your help would be appreciated for the below array concept I am trying to work out.

How can I make the below coding shorter so that I can reduce the amount of If Statements. So when a "battlename = name[0]" index is selected the statement automatically selects the corresponding monsters at the same index level without having to use so many If statements.

Hope I'm making sense.

var names = ["Lancelot", "Arthur", "Gawain", "Galahad"]
var monsters = ["Dragon", "Boar", "Giant", "Griffin"]
let battlename = names[1]
print(battlename, "Vs.", monsters)

if battlename == names[0] {
print(battlename, "Vs.", monsters[0])
}
else if battlename == names[1] {
print(battlename, "Vs.", monsters[1])
}
else if battlename == names[2] {
print(battlename, "Vs.", monsters[2])
}
else if battlename == names[3] {
print(battlename, "Vs.", monsters[3])
}

Eric Aya · Accepted Answer · 2016-03-17 12:13:42Z

7

You can replace all your conditions with this single one:

if let index = names.indexOf(battlename) {
    print(battlename, "Vs.", monsters[index])
}

Also, a tip if you want to print the list of the monsters names in your intro, instead of just printing the array you can join the items as a string:

print(battlename, "Vs.", monsters.joinWithSeparator(", ")) // "Arthur Vs. Dragon, Boar, Giant, Griffin"

answered Mar 17, 2016 at 12:13

Eric Aya

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Russell · Accepted Answer · 2016-03-17 12:15:54Z

0

    var names = ["Lancelot", "Arthur", "Gawain", "Galahad"]
    var monsters = ["Dragon", "Boar", "Giant", "Griffin"]
    let battlename = names[1]

    var index = names.indexOf(battlename)
    if index != nil
    {
        print(battlename, "Vs.", monsters[index!])
    }
    else
    {
        print("No match")
    }

answered Mar 17, 2016 at 12:15

Russell

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