interface Foo<T> { ... }
class Bar implements Foo<Baz> { ... }
I've got a Bar object. How to get the value of T for it (Baz)?
So far, I only managed to get the interface and T, but I can't see a way to get its value.
Thanks in advance.
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2 Answers
Type type = bar.getClass().getGenericInterfaces()[0];
if (type instanceof ParameterizedType) {
Type actualType = ((ParameterizedType) type).getActualTypeArguments()[0];
System.out.println(actualType);
}
Of course, in the general case, you should iterate over the array, rather than assuming it has excatly one element ([0]). With the above example, you can cast actualType to java.lang.Class. In other cases it may be different (see comment by meriton)
If you already have Guava on the classpath, this is a bit more robust as you specify the interface/superclass by type rather than index.
TypeToken<?> baz = TypeToken.of(Bar.class).resolveType(Foo.class.getTypeParameters()[0]);
System.out.println(baz.getRawType()); // class Baz
