Function syntax error in PHP

Question

Does anyone know this PHP function syntax and how it works? It's not working with PHP 5.5

    public function getProxiesTargetDir() : string
    {
        return $this->proxiesTargetDir ?: $this->proxiesTargetDir = sys_get_temp_dir();
    }

I know that guys, but a external library have this sintaxis. See the edit — Carlos Gomez
– Carlos Gomez, Commented Mar 19, 2016 at 16:12

ceejayoz · Accepted Answer · 2016-03-19 17:10:39Z

4

You are using typed returns public function getProxiesTargetDir() : string which only exists starting from PHP 7.

For previous versions just remove : string > public function getProxiesTargetDir() {}

edited Mar 19, 2016 at 17:10

ceejayoz

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answered Mar 19, 2016 at 17:05

Maks3w

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1 Comment

ceejayoz Over a year ago

And if it's an external library, you'll need to use an older PHP5-compatible version of it.

KIMB-technologies · Accepted Answer · 2016-03-19 17:39:32Z

-1

You are using the shorthand if/else syntax of PHP here, but let's use the long way:

public function getProxiesTargetDir()
{
    if( $this->proxiesTargetDir ==  false ){
           return ( $this->proxiesTargetDir = sys_get_temp_dir() );
    }
    else{ 
          return $this->proxiesTargetDir;
   }
}

If have also deleted the :string, because it can make errors and it is not really necessary here.

edited Mar 19, 2016 at 17:39

answered Mar 19, 2016 at 17:03

KIMB-technologies

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