Swift convert HexString to Integer

Question

I have a data source in String example

HexString = "72AE"

and i would like to convert it into byte and store into byte array

bytearray = [72, AE]  //UInt8

i know i can do this by

let hexaString = "72AE"
let resultArray = hexaString.characters.map{Int(strtoul(( String($0)), nil, 16))}

print(resultArray)  // "[7, 2, 10, 14]"

but it is not returning the value i want. I have also tried to chop it into hexaString1 = "72" hexaString2 = "AE" but still i can't manage to get the correct value.

Muzahid · Accepted Answer · 2016-03-20 05:34:28Z

1

Hope this will help you

let hexaString = "72AE"
var byteArray = [UInt8]()
byteArray += hexaString.utf8  // Convert into byte array

// Retain the orginal string from byte array
let stringFromByteArray = NSString(bytes: byteArray, length: byteArray.count, encoding: NSUTF8StringEncoding)

answered Mar 20, 2016 at 5:34

Muzahid

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1 Comment

John Smith Over a year ago

I assume he wanted 0x72 and 0xAE returned, That just gets 0x37 (7), 0x32 (2), 0x41 (A), 0x45 (E)

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