I want to make a string array with values of names and some numbers(which are strings)
i want to pass them into a function that will take the array and then split them into an object jagged array (1 array of strings and 1 array of ints)
the array is:
string[] str= { "toto", "the", "moto", "my", "friend","12","13","14","99","88"};
and the function looks like this:
public object[][] bloop (string[] bstr)
{
}
whats next?
Your scenario looks like bad design that can cause errors and performance issues. The better way is to change code for using generic List<> or something like that. But in your current problem you can use below code:
public object[][] bloop (string[] bstr)
{
var numbers = new List<int>();
var strings = new List<string>();
var result = new object[2][];
foreach(var str in bstr)
{
int number = 0;
if(int.TryParse(str, out number))
{
numbers.Add(number);
}
else
{
strings.Add(str);
}
}
result[0] = strings.ToArray();
result[1] = numbers.ToArray();
return result;
}
public static object[][] bloop(string[] bstr)
{
object[][] result = new object[2][] { new object[bstr.Length], new object[bstr.Length] };
int sFlag = 0, iFlag = 0, val;
foreach (string str in bstr)
if (int.TryParse(str, out val))
result[1][iFlag++] = val;
else
result[0][sFlag++] = str;
return result;
}
new object[bstr.Length]; that's why tail items of bloop will be nulls
I agree that your requirement sounds odd and should be solved with a different approach. However, this will do what you want:
public T[][] Bloop<T>(T[] items)
{
if (items == null) throw new ArgumentNullException("items");
if (items.Length == 1) return new T[][] { items, new T[] { } };
int firstLength = (int) Math.Ceiling((double)items.Length / 2);
T[] firstPart = new T[firstLength];
Array.Copy(items, 0, firstPart, 0, firstLength);
int secondLength = (int)Math.Floor((double)items.Length / 2);
T[] secondPart = new T[secondLength];
Array.Copy(items, firstLength, secondPart, 0, secondLength);
return new T[][] { firstPart, secondPart };
}
Your sample:
string[] str= { "toto", "the", "moto", "my", "friend","12","13","14","99","88"};
string[][] result = Bloop(str);
If you need the second array as int[] you could use following:
int[] ints = Array.ConvertAll(result[1], int.Parse);
Linq solution.
You have two groups: first one has items that can be parsed to int and the second group contains all the others, so GroupBy looks quite naturally:
public Object[][] bloop(string[] bstr) {
if (null == bstr)
throw new ArgumentNullException("bstr");
int v;
return bstr
.GroupBy(x => int.TryParse(x, out v))
.OrderBy(chunk => chunk.Key) // let strings be the first
.Select(chunk => chunk.ToArray())
.ToArray();
}
Test:
string[] str = { "toto", "the", "moto", "my", "friend", "12", "13", "14", "99", "88" };
// toto, the, moto, my, friend
// 12, 13, 14, 99, 88
Console.Write(String.Join(Environment.NewLine,
bloop(str).Select(x => String.Join(", ", x))));