how to extract or get int vaue from string in a hashmap value

Question

HashMap<String,String> dataRules = new HashMap<String,String>();

dataRules.put("FAX_GW_NW_ELE_DM_","VARCHAR2(32 BYTE)");

In the above given expression I need to extract 32 BYTE as int 32 from value to use. Can anyone suggest how I can do this?

As an aside, it's worth noting that your problem really doesn't have anything to do with the fact the value is in a map. You're trying to extract the int value 32 from the string "VARCHAR2(32 BYTE)" - where that string comes from is at least somewhat irrelevant. — Jon Skeet
– Jon Skeet, Commented Mar 24, 2016 at 14:24
@JonSkeet my bad, didn´t really see the 2 in the varchar... — SomeJavaGuy
– SomeJavaGuy, Commented Mar 24, 2016 at 14:30
I am trying with substring , hope it will work ,its ok . thanks — Vikas Rajak
– Vikas Rajak, Commented Mar 24, 2016 at 14:31

The Roy · Accepted Answer · 2016-03-24 14:55:59Z

1

package general;

import java.util.ArrayList;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class MatchNumber {

    public static ArrayList<Integer> extractInt(String mapValue) {
        Matcher matcher = Pattern.compile("\\d+").matcher(mapValue);

        //  throw new NumberFormatException("For input string [" + mapValue + "]");
        ArrayList<Integer> array = new ArrayList<Integer>();
        while (matcher.find()){
            array.add(Integer.parseInt(matcher.group()));
        }
        return array;
    }

public static void main(String[] args){
    ArrayList<Integer> result = extractInt("VARCHAR2(32 BYTE)");
    for (int i : result){
        System.out.println(i);
    }

  }
}

edited Mar 24, 2016 at 14:55

answered Mar 24, 2016 at 14:24

The Roy

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2 Comments

Jon Skeet Over a year ago

In the OP's case, that will return 2 due to the VARCHAR2.

The Roy Over a year ago

Now this example should print both 2 as well as 32

Narendra Jaggi · Accepted Answer · 2016-03-24 15:42:27Z

1

Assuming you have the fixed prefix and sufix you can extract it like this

Integer.valueOf(strVal.substring(9,strVal.indexOf("BYTE)") ))

where 9 is length of "VARCHAR2(" plus 1

edited Mar 24, 2016 at 15:42

Narendra Jaggi

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answered Mar 24, 2016 at 14:30

Radu Ionescu

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2 Comments

Evgeny Over a year ago

Actually it doesn't work. strVal.indexOf("VARCHAR2(") returns 0. So substring method returns "VARCHAR2(32" instead of 32

Radu Ionescu Over a year ago

Correct, I modified it.

SomeJavaGuy · Accepted Answer · 2016-03-24 14:40:07Z

0

in case the the type value, as varchar2, will differ, but the number will be allways written in paranthesis you could use String#replaceAll with a capturing group to extract the number.

String input = "VARCHAR2(32 BYTE)";
System.out.println(input.replaceAll(".*\\((\\d*).*", "$1"));

output

edited Mar 24, 2016 at 14:40

answered Mar 24, 2016 at 14:34

SomeJavaGuy

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