python selenium click on a link button

Question

I am quite new to python selenium and I am trying to click on a button which has the following html structure:

<a href="#" onclick="loadCalendarsForDateFn('jmpto1605')"><span class="jumpToMonthMM">May</span><span class="jumpToMonthYY">2016</span></a><br/>

I would like to be able to click the "May 2016" button above. Can someone guide me how to do that?

Thanks in advance!

alecxe · Accepted Answer · 2016-03-25 20:23:14Z

2

You can check both month and year with an XPath:

//a[span[@class="jumpToMonthMM"] = "May" and
    span[@class="jumpToMonthYY"] = "2016"]

answered Mar 25, 2016 at 20:23

alecxe

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6 Comments

damingzi Over a year ago

Thanks a lot! I found the link button! One followup question is when I issue the click() command, it just didn't jump to the May 2016.

elem = browser.find_element_by_xpath('//a[span[@class="jumpToMonthMM"] = "May" and span[@class="jumpToMonthYY"] = "2016"]')

print('Found It!') elem.click()

alecxe Over a year ago

@damingzi great! Do you mean nothing happens when you issue a click()? What if you would move to the element and then click: ActionChains(driver).move_to_element(elem).click().perform()? Don't forget the import: from selenium.webdriver.common.action_chains import ActionChains.

damingzi Over a year ago

Thanks for your continuous replies. But the ActionChains click didn't work neither. I am thinking if the elem "May 2016" is the correct one to click. Do you have any clue?

alecxe Over a year ago

@damingzi could you please elaborate this problem into a separate question? This might make more sense since more people may help. Make sure to provide all the necessary details. Thanks!

damingzi Over a year ago

Thanks! I found a workaround for click(). I substituted .click() with .send_keys("\n"), the latter one does almost the same thing :)

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Padraic Cunningham · Accepted Answer · 2016-03-25 20:36:27Z

1

Alexce has a good solution but you could also look for the onclick attribute with loadCalendarsForDateFn('jmpto1605'):

find_element_by_xpath("""//a[@onclick ="loadCalendarsForDateFn('jmpto1605')"]""")

The 05 and 16 obviously correspond to May and 2016 as so I think it is safe to assume it is unique.

answered Mar 25, 2016 at 20:36

Padraic Cunningham

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1 Comment

damingzi Over a year ago

Thank you Padraic for your input :) I tried similar approach below, and it also worked! find_element_by_xpath(".//a[contains(@onclick, 'jmpto1605')]")

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