Passing variable value in php array

Question

I have array in php like:

if ($_GET['id1'] == "machine-category") {
    $table['cols'] = array(
        array('label' => 'category', 'type' => 'string'),
        array('label' => 'count', 'type' => 'string')
    );
}

I want to pass various value in category, tried:

if ($_GET['id1'] == "machine-category") {
    $table['cols'] = array(
        array("'".
            "label".
            "'".
            " => . ".
            "'".explode($GET['id1'], "-")[1].
            "', '".
            "type'".
            " => '".
            "string".
            "'"),
        array('label' => 'count', 'type' => 'string')
    );
}

but it doesn't work.

Can anyone provide the solution for same?

Could you provide more details on how, exactly, it is not working? — Castaglia
– Castaglia, Commented Mar 26, 2016 at 3:38

David White · Accepted Answer · 2016-03-26 03:55:49Z

2

I'm not quite sure what you're trying to accomplish. Perhaps you're saying that if your $_GET['id1'] is machine-category, you want a line that looks like this:

    array('label' => 'category', 'type' => 'string'),

and if you have a $_GET['id1'] of machine-foobar then you want a line like this:

    array('label' => 'foobar', 'type' => 'string'),

Is that what you're asking? In that case, try this:

if ($_GET['id1'] == "machine-category!") {
        $category_parts = explode('-', $_GET['id1']);
        $category = $category_parts[1];
        $table['cols'] = array(
            array('label' => $category, 'type' => 'string'),
            array('label' => 'count', 'type' => 'string')
        );
}

answered Mar 26, 2016 at 3:55

David White

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