Variable function compatibility with PHP 7 and PHP5

Question

I have a situation where this works in PHP5 but fatals in PHP7:

/* load batch processing data into variable */
$args = get_option('leads_batch_processing');
/* process batches */
self::$args['method']($args);

And this works in PHP7 but fatals PHP5:

/* load batch processing data into variable */
$args = get_option('leads_batch_processing');
/* process batches */
 self::{$args['method']}($args);

How can I use the variable function successfully in both PHP environments? I tried using an if condition based on PHP version but the PHP7 version's syntax fatals PHP5 so I cannot go that route.

What do I do?

Could you propose it as an answer? In the case above $args is not a private or static variable. But inside $args['method'] there is a function name that exists within the calling class (self::) — atwellpub
– atwellpub, Commented Mar 26, 2016 at 20:11
The second code should work on both PHP 5 and PHP 7. Make sure you're not testing on some outdated PHP version (like 5.3). — NikiC
– NikiC, Commented Mar 26, 2016 at 20:39
I can't afford that context working as a WordPress plugin developer I will see PHP version from 5.3 to 7. The second version will fatal on a lower version of PHP. It doesn't like the brackets. — atwellpub
– atwellpub, Commented Mar 26, 2016 at 21:15

NikiC · Accepted Answer · 2016-03-27 12:10:27Z

2

Assign it to a regular variable, which wouldn't cause a syntax error:

$method = $args['method'];
$this->$method($args);

Or, similarly to what was suggested in the comments, use call_user_func():

call_user_func(
    array($this, $args['method']),
    $args
);

edited Mar 27, 2016 at 12:10

NikiC

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answered Mar 26, 2016 at 22:57

Narf

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