Changing values in a nested JSON object

Question

I've got a JSON object like this

var test = {
    "value1": "",
    "array1": {
       "value2": 0,
       "value3": 0
    }
}

Now I want to Iterate over array1 in the test JSON and multiply the values and store them again ...

I tried it this way but it doesn't store it

jQuery.each(test.array1, function (i, val) {
    test.array1.i = val * 1.3;
});

The multiplication works fine .. But how to restore it properly?

It's not really clear what you're asking. Could you post your expected output? — millerbr
– millerbr, Commented Mar 28, 2016 at 13:51
You really don't even need val at all, you can just use *=. Also, a plain old for..in loop is even better. — castletheperson
– castletheperson, Commented Mar 28, 2016 at 14:55

Tushar · Accepted Answer · 2016-03-28 13:52:49Z

3

You can use Array#forEach on keys array which are get by using Object.keys().

Object.keys(test.array1).forEach(function(key) {
    test.array1[key] *= 1.3;
});

Using Arrow function:

Object.keys(test.array1).forEach(key => test.array1[key] *= 1.3);

var test = {
    "value1": "",
    "array1": {
        "value2": 10,
        "value3": 30
    }
};

Object.keys(test.array1).forEach(function(key) {
    test.array1[key] *= 1.3;
});

console.log(test);

answered Mar 28, 2016 at 13:52

Tushar

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1 Comment

castletheperson Over a year ago

Wow, a plain javascript solution that's just as concise as jQuery

Ibrahim Khan · Accepted Answer · 2016-03-28 13:51:54Z

2

Use test.array1[i] instead of test.array1.ilike following.

jQuery.each(test.array1, function (i, val) {
    test.array1[i] = val * 1.3;
});

answered Mar 28, 2016 at 13:51

Ibrahim Khan

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Comments

Cyril Cherian · Accepted Answer · 2016-03-28 13:52:50Z

2

Do it like this:

var test = {
    "value1": "",
    "array1": {
       "value2": 1,
       "value3": 0
    }
}
jQuery.each(test.array1, function (i, val) {
                    console.log(i, val)
                    test.array1[i] = val * 1.3;//instead of test.array1.i = val * 1.3; use the bracket notation
                });

console.log(test)

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

answered Mar 28, 2016 at 13:52

Cyril Cherian

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Comments

castletheperson · Accepted Answer · 2016-03-28 14:35:01Z

2

Without jQuery it can be done like this:

var test = {
  "value1": "",
  "array1": {
    "value2": 1,
    "value3": 2
  }
}

for (key in test.array1) {
  test.array1[key] *= 1.3;
}

console.log(test);

Run the snippet to check how it works.

edited Mar 28, 2016 at 14:35

castletheperson

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answered Mar 28, 2016 at 14:05

nim118

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