I have a large string in the format of the following:
'324/;.ke5 efwef dwe,werwrf <>i want this<> ergy;'56\45,> thu ;lokr<>i want this<> htur ;''\> htur> jur'
i know that i can do something along the lines of:
result= text.partition('<>')[-1].rpartition('<>')[0]
but this will just give me what is in between the first <> and the last <> in the string , how can i loop through the whole string and extract what is in between each respective <> <> tag pair?
You can use regular expressions and findall():
>>> import re
>>> s = "324/;.ke5 efwef dwe,werwrf <>i want this<> ergy;'56\45,> thu ;lokr<>i want this<> htur ;''\> htur> jur"
>>> re.findall(r"<>(.*?)<>", s)
['i want this', 'i want this']
where (.*?) is a capturing group that would match any characters any number of times in a non-greedy mode.
I think string.split() is what you want:
>>> text = """'324/;.ke5 efwef dwe,werwrf <>i want this<> ergy;'56\45,> thu ;lokr<>i want this<> htur ;''\> htur> jur'"""
>>> print text.split('<>')[1:-1]
['i want this', " ergy;'56%,> thu ;lokr", 'i want this']
The split() method gives you a list of strings where the argument is used as the delimiter. (https://docs.python.org/2/library/string.html#string.split) Then, [1:-1] gives you a slice of the list without the first and last elements.
