C++ Multidimensional string arrays

Question

Can someone please correct this code for me, so it can produce the correct output. The code is to display the name of the patient, the doctor that treated him/her, the room where he/she was treated.

#include <iostream> 
using namespace std;

int main()
{
    string bisi[3][4] = {{"      ", "DOCTOR 1", "DOCTOR 2", "DOCTOR 3"},
{"ROOM 1", "AFUAH", "ARABA", "JOHNSON"},
{"ROOM 2", "BENJAMIN", "KOROMA", "CHELSEA"}};

    for (int row=0; row<3; row++){
        for (int col=0; col<4; col++){
            cout<<bisi [row][col]<<" "; /*I get error on this line.The angle bracket "<<" Error Message: No operator matches this operand.*/
        }
        cout<<endl;
    }

    return 0;
}

Can you identify what each element of bisi is supposed to mean please (and what their relation ship should be). Perhaps show us the output you want to see. — Martin Bonner supports Monica
– Martin Bonner supports Monica, Commented Mar 30, 2016 at 10:12
I accept this as a beginner's test program. But note that idiomatic C++ would not model a patient / doctor / room relationship in a multidimensional (C...) array like this. You would have class Doctor, class Patient, ... — DevSolar
– DevSolar, Commented Mar 30, 2016 at 10:17
if you're using c++ take advantage of its functionality and library. use a vector. if not just use plain C. — user3477273
– user3477273, Commented Mar 30, 2016 at 10:45
I am still a beginner please, i just need this done for an assignment given to me by my lecturer. Thanks — Sir_Martins
– Sir_Martins, Commented Mar 30, 2016 at 11:21

DimChtz · Accepted Answer · 2016-03-30 10:33:17Z

3

You need to change:

cout << bisi[row] << bisi[col] << " ";

to:

 cout << bisi[row][col] << " ";

bisi is a 2d array, bisi[row] or bisi[col] will just print you an address

edited Mar 30, 2016 at 10:33

answered Mar 30, 2016 at 10:12

DimChtz

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3 Comments

Sir_Martins Over a year ago

i used cout << bisi[row][col] << " "; but i get this "<<" error @DimChtz

DimChtz Over a year ago

@Sir_Martins Can you update the question with the new code and the error you get?

Sir_Martins Over a year ago

I changed my data type from "string" to "int" the code worked without error.

Lanting · Accepted Answer · 2016-03-30 10:22:32Z

1

From an object oriented view point, this is bad style. Wrap the information in a class. e.g.

struct Appointment
{
  std::string patient;
  std::string doctor;
  std::string room;
}

and store that information in some kind of collection:

std::vector<Appointment> appointments;
appointments.emplace_back({"henk", "doctor bob", "room 213"});
appointments.emplace_back({"jan", "doctor bert", "room 200"});

printing could then be done by:

for (const auto &appointment: appointments)
{
  std::cout << appointment.patient
            << appointment.doctor
            << appointment.room
            << std::endl;
}

answered Mar 30, 2016 at 10:22

Lanting

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Comments

Sir_Martins · Accepted Answer · 2016-03-30 16:46:28Z

0

I just added the preprocessor directive #include <"string"> without the quotes and it worked fine. Thank You guys for helping out.

answered Mar 30, 2016 at 16:46

Sir_Martins

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