Java regular expression extract special string between two string

Question

currently I wish to extract a Token that is content in string format. I've already seen this topic, but in my context, I don't manage to extract my token. I've got this code:

import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class SOAPParsing {
    public static void main(String[] args) {
        String test = "<BinarySecurityToken Id=\"TotoToken\">Kqdsqd/Jxugtqsk6Ws3q3sd54sq6d4q6sd4qs6d4qs6dq6sd98d69qdq9dsq7d98q7sdqdq7qsddq7Mw2RMmhevkJt/4q6sd7qsIRveuTTqdqsa/zxqsdqdqNg==</BinarySecurityToken>";
        Pattern pattern = Pattern.compile("BinarySecurityToken\\\\Id=\"TotoToken\">\\s:\\s(.+?)\\</BinarySecurityToken>");
        Matcher matcher = pattern.matcher(test);
        if (matcher.find()) {
            System.out.println(matcher.group(1));
        } else {
            System.out.println("nothing ..");
        }
    }
}

How I can fix my problem ?

Thanks in advance,

Try your regex in some online tool first, i.e. without the Java escaping. As an example: what do you think \\ (non-escaped version) after BinarySecurityToken should match? — Thomas
– Thomas, Commented Mar 31, 2016 at 13:40
For one thing the part of your Regex, \s:\s is looking to match [whitespace]:[whitespace] which doesn't appear in your string. So even if everything else were correct (which I doubt), it still wouldn't match. Like Thomas said, Google "Regex Tester" and get the pattern to work before you mess with stuffing it in Java. — Duston
– Duston, Commented Mar 31, 2016 at 13:57

Zach Olivare · Accepted Answer · 2016-03-31 13:50:59Z

1

Try this as your regex:

"<BinarySecurityToken Id=.*>(.*)</BinarySecurityToken>"

answered Mar 31, 2016 at 13:50

Zach Olivare

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