String format using regex in Scala

Question

I have a String in the format of "20150403" and I want to convert it into the format of string like "2015-04-03". Is there any way using regular expression and string format in Scala?

Rahul · Accepted Answer · 2016-04-01 06:39:18Z

2

Here is a sample

val date = """(\d{4})(\d{2})(\d{2})""".r
val date(year, month, day) = "20150402"
println(s"$year-$month-$day") // 2015-04-02

answered Apr 1, 2016 at 6:39

Rahul

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Comments

Himaprasoon · Accepted Answer · 2016-04-01 07:18:07Z

1

Regex is slow. For this u need not use regex , u can use string.substring .

val today="20150403"
val out=today.substring(0,4)+"-"+today.substring(4,6)+"-"+today.substring(6)

answered Apr 1, 2016 at 7:18

Himaprasoon

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1 Comment

jwvh Over a year ago

Or f"${today}%.4s-${today.drop(4)}%.2s-${today.drop(6)}"

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