Oracle based PIVOT with multiple columns group

You are pivoting on a fixed value, the string literal 'RM', so you're really not doing anything useful in the pivot - the output is the same as you'd get from running the 'pivot_data' query on its own:

SELECT eNAME,workhrs,room, SCR from PRODUCTIVITY p,PRODUCTIVITYd d, emp e, ROOMS R
where p.PRODUCTIVITYID=d.PRODUCTIVITYID and e.empno=p.employeeid
AND R.ID=P.ROOMID;

ENAME    WORKHRS       ROOM        SCR
----- ---------- ---------- ----------
JONES        3.6        101         53
ALLEN       1.32        101         43
ALLEN          6        102         22

You want the aggregate workhrs for each employee, and a pivot of the rooms they sold. If you change that query to get the analytic sum of workhrs and a ranking of the room/scr values (and using modern join syntax) you get:

select e.ename, r.room, p.scr,
  sum(d.workhrs) over (partition by e.ename) as wrkhrs,
  rank() over (partition by e.ename order by r.room, p.scr) as rnk
from productivity p
join productivityd d on d.productivityid = p.productivityid
join emp e on e.empno=p.employeeid
join rooms r on r.id = p.roomid;

ENAME       ROOM        SCR     WRKHRS        RNK
----- ---------- ---------- ---------- ----------
ALLEN        101         43       7.32          1
ALLEN        102         22       7.32          2
JONES        101         53        3.6          1

You can then pivot on that generated rnk number:

with pivot_data as (
  select e.ename, r.room, p.scr,
    sum(d.workhrs) over (partition by e.ename) as wrkhrs,
    rank() over (partition by e.ename order by r.room, p.scr) as rnk
  from productivity p
  join productivityd d on d.productivityid = p.productivityid
  join emp e on e.empno=p.employeeid
  join rooms r on r.id = p.roomid
)
select *
from   pivot_data
pivot (
  min(room) as room, min(scr) as scr  --<-- pivot_clause
  for rnk                             --<-- pivot_for_clause        
  in  (1, 2, 3)                       --<-- pivot_in_clause         
);

ENAME     WRKHRS     1_ROOM      1_SCR     2_ROOM      2_SCR     3_ROOM      3_SCR
----- ---------- ---------- ---------- ---------- ---------- ---------- ----------
ALLEN       7.32        101         43        102         22                      
JONES        3.6        101         53                                            

You need to know the maximum number of rooms any employee may have - i.e. the highest rnk could ever be - and include all of those in the in clause. Which means you're likely to end up with empty columns, as in this example where there is no data for 3_room or 3_scr. You can't avoid that though, unless you get an XML result or generate the query dynamically.

What you are saying makes no sense. What do you mean by "pivot RM_ROOM"? So I have to guess. I am guessing you want to group employees and sum workhrs, and then pivot the result. The "Output" you show seems to be the output for pivot_data, your subquery.

Your answer will only have eNAME and for each of them, a count of hours worked. So you don't need to SELECT the room numbers in the pivot_data subquery. You only need eNAME and workhrs. Then it is a simple matter of using the PIVOT syntax:

WITH pivot_data AS (
    SELECT eNAME, workhrs FROM PRODUCTIVITY p,PRODUCTIVITYd d, emp e, ROOMS R
    where p.PRODUCTIVITYID=d.PRODUCTIVITYID and e.empno=p.employeeid
    AND R.ID=P.ROOMID
            )
SELECT *
FROM   pivot_data
PIVOT (
        SUM(workhrs)
        FOR eNAME IN ('JONES', 'ALLEN')
      )
/

Output:

   'JONES'    'ALLEN'
---------- ----------
       3.6       7.32