Python integrate.quad(1/function) error

Question

I have the following existing code:

integrate.quad(somefunc, lowerbound, upperbound)

However I want to change this to

integrate.quad(1/somefunc, lowerbound, upperbound)

but I get operand errors. Is there a way I can do this without changing somefunc?

Ignacio Vazquez-Abrams · Accepted Answer · 2016-04-04 15:08:33Z

1

You want to use a lambda to call the function appropriately, similar to so:

integrate.quad(lambda x: 1/somefunc(x), lowerbound, upperbound)

answered Apr 4, 2016 at 15:08

804k160 gold badges1.4k silver badges1.4k bronze badges

Sign up to request clarification or add additional context in comments.

1 Answer 1