php make a json object not working as expected

Question

This is my code:

$amenitiesObject = array('parameter-amenities' => array('value' =>  $amenities));
$buildingObject = array('parameter-building' => array('value' =>  $building));

$data = array($amenitiesObject, $buildingObject);
$post_data = json_encode($data, JSON_FORCE_OBJECT);
return $post_data;

the result is:

{"0":{"parameter-amenities":{"value":""}},"1":{"parameter-building":{"value":""}}}

while i was hoping for this:

{"parameter-amenities":{"value":""},"parameter-building":{"value":""}}

what is my mistake please?

$data = array_merge( $amenitiesObject, $buildingObject );

fusion3k
– fusion3k

2016-04-05 00:40:23 +00:00
Commented Apr 5, 2016 at 0:40 — fusion3k
– fusion3k, Commented Apr 5, 2016 at 0:40
@fusion3k yes works, thanks

Anastasie Laurent
– Anastasie Laurent

2016-04-05 00:42:43 +00:00
Commented Apr 5, 2016 at 0:42 — Anastasie Laurent
– Anastasie Laurent, Commented Apr 5, 2016 at 0:42

Growiel · Accepted Answer · 2016-04-05 01:10:23Z

1

While @fusion3k's comment is correct and doing $data = array_merge( $amenitiesObject, $buildingObject ); fixes it, I'd like to explain it a little further so you can avoid this type of scenario.

When you do $data = array($amenitiesObject, $buildingObject);, you are not creating a merge of both arrays, you are creating an array with index 0 equals to $amenitiesObject and index 1 equals to $buildingObject, the equivalent of doing :

array(0 => $amenitiesObject, 1 => $buildingObject);

So the json_encode part is working as expected.

When you use array_merge, you maintain only ONE array, that is a combination on both arrays, so you have the expected result.

answered Apr 5, 2016 at 1:10

Growiel

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