Bash script need array values in for loop

Question

i have array values as below and used in below for loop.

a=(400 402 403 404)

for i in "${a[@]}"
do
echo $i;
done

output

I need to take array values one by one and use as below.

for i in "${a[@]}"
do
awk '{if($8==$i) print} filename.log | wc -l;
done

i need find the errors count in httpderror.log so i am passing http error codes one by one to check file and print count of error found in each http code. Http error found in 8th column ($8==$i).

output should be error count of matched lines like 400 - 44, 402 -43 but need only values as below..

 44
 43
 42

Please help me how to do this....

Thanks guys, it worked

Sasee
– Sasee

2016-04-06 14:31:13 +00:00
Commented Apr 6, 2016 at 14:31 — Sasee
– Sasee, Commented Apr 6, 2016 at 14:31

anubhava · Accepted Answer · 2016-04-05 20:56:42Z

5

You can do this:

for i in "${a[@]}"
do
   awk -v code="$i" '$8==code{c++} END{print code, "-", c}' filename.log
done

However I suggest doing it directly in awk and avoid invoking awk command for every element in array.

awk 'BEGIN {
   a[400]=a[402]=a[403]=a[404]=0
}
$8 in a {
   a[$8]++
}
END { 
   for (i in a)
      print i, "-", a[i]
}' filename.log

edited Apr 5, 2016 at 20:56

answered Apr 5, 2016 at 20:32

anubhava

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Comments

Munir · Accepted Answer · 2016-04-05 20:32:24Z

1

Try this:

for i in "${a[@]}"
do
    awk '{print $8}' filename.log | grep $i | wc -l
done

answered Apr 5, 2016 at 20:32

Munir

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Comments

Henk Langeveld · Accepted Answer · 2016-04-05 20:35:52Z

1

Mixing data structures between two separate scripting languages is asking for trouble.

Based on the original question, you want exact matches for 400,402,403, and 404 in column 8.

Using regular expressions, you can do this in awk alone.

awk '$8 ~ /^40[0234]$/ {n++} END {print n}' filename.log

A shorter version would be:

awk '$8 ~ /^40[0234]$/' filename.log | wc -l

(but awk can do the counting just as well).

edited Apr 5, 2016 at 20:35

answered Apr 5, 2016 at 20:31

Henk Langeveld

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2 Comments

karakfa Over a year ago

perhaps ...{a[$8]++} END{for(k in a) ...

Henk Langeveld Over a year ago

@karafka yup, just like anubhava's solution. I missed out on that part, but that's how I'd do that.

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