getting list of top space consuming files and remove it

Question

I am using du -hsx * | sort -rh | head -10 to get top 10 space consuming files in directory. So I would like to know how to pass output of above command and delete those files. I know about xargs but I don't know how to incorporate it in my command, so any help would be appreciated ?

Thanks

Sandeep Sukhija · Accepted Answer · 2016-04-07 10:46:12Z

2

You can do something like this:

du -sxh * | sort -rh | head -10 | xargs rm -fr $1

answered Apr 7, 2016 at 10:46

Sandeep Sukhija

1,17617 silver badges31 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Rahul Over a year ago

Thank you so much. Could you please explain what $1 will do ?

Sandeep Sukhija Over a year ago

$1 is the input to the xargs received from the output generated from head

Rahul · Accepted Answer · 2016-06-13 13:27:53Z

1

You can do,

du -sxh * | sort -rh | head -10 > out
cat out | xargs rm -fr $1

edited Jun 13, 2016 at 13:27

Rahul

4183 gold badges9 silver badges25 bronze badges

answered Jun 13, 2016 at 10:55

sudhir kumar mishra

1161 silver badge8 bronze badges

1 Comment

sudhir kumar mishra Over a year ago

where $1 is output of first one as input of second one.

Collectives™ on Stack Overflow

getting list of top space consuming files and remove it

2 Answers 2

2 Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

2 Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related