Getting Array Out Of Bounds Error in Java

Question

I am new to Java and i wrote a simple program that calculates the sum of multiples of 3 below 10. I am not sure why i am getting Array Out Of Bounds Exception

int a[] = {},j = 0,sum = 0;
        for(int i=1;i<=10;i++)
        {
            if ((i % 3) == 0)
            {
            a[j] = i; // Here, i am getting the exception
            j++;
            }
        }
        for(int i1=0;i1<j;i1++)
        {
            sum = sum + a[i1];
        }
        System.out.println(sum);
     }

Arrays are static. Since you defined it as having 0 values in int a[] = {}, you will get an outOfBoundsException by trying to set a value of any index in the array. You will need to either set the values of the array or set a size for the array (in which case all positions will be automatically filled with 0). — Zulfe
– Zulfe, Commented Apr 9, 2016 at 3:06
Thank You very much. I believe it was too silly for this forum — Sourav Das
– Sourav Das, Commented Apr 9, 2016 at 3:09

HenryDev · Accepted Answer · 2016-04-09 03:07:57Z

2

Here's the solution. You were just missing defining the size of the array. Hope it helps :).

public final class Program {

public static void main(String[] args) {

    int a[] = new int[10] , j = 0, sum = 0;
    for (int i = 1; i <= 10; i++) {
        if ((i % 3) == 0) {
            a[j] = i; // Here, i am getting the exception
            j++;
        }
    }
    for (int i1 = 0; i1 < j; i1++) {
        sum = sum + a[i1];
    }
    System.out.println(sum);
}
}

answered Apr 9, 2016 at 3:07

HenryDev

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