Passing and using struct with typedef

Question

how can i use the next struct with typedef by passing it to another function like that?

I have tried this code but i doesn't seem to be working.

typedef struct stru{
    int num;
} stru;

int main(void)
{
    stru current;
    struc(&current);
    printf("%d", current.num);
}


int struc(stru* current)
{
    *current.num = 1;
    return 0;
}

It didn't worked because its not the right way to set it to 1 i guess can someone help me to do it , i have tried few other ways but neither of them is working

*current.num = 1;

@SLaks well its not workint to set *current.num = 1; by that way — user23634623
– user23634623, Commented Apr 12, 2016 at 21:39
current->num = 1; postfix has higher precedence than unary. — user3185968
– user3185968, Commented Apr 12, 2016 at 21:39

SLaks · Accepted Answer · 2016-04-12 21:43:38Z

2

Unary * has less precedence than ..

Therefore, your code is parsed as *(current.num) = 1, which is very much not what you want.

Instead, you need to force the dereference to happen first: (*current).num.

This is so common that C has a shorthand for it: current->num.

edited Apr 12, 2016 at 21:43

answered Apr 12, 2016 at 21:39

SLaks

891k182 gold badges1.9k silver badges2k bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

SLaks Over a year ago

Oops; the * should have been inside the parentheses.

Collectives™ on Stack Overflow

Passing and using struct with typedef

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related