Hide command not found bash script

Question

How can I hide the command not found in my bash script? Im curious because everything works great except the sloppy "command not found message"

read user_name
if $user_name && exit 2> /dev/null
then
        exit 0
elif egrep "^${user_name}": /etc/passwd 2> /dev/null
then
        finger $user_name
        exit 0
elif
        until egrep "^${user_name}:" /etc/passwd || $user_name && "exit"  2> /dev/null
        do
        echo "try again or type exit to quit"
        read user_name
        if egrep -i "^${user_name}": /etc/passwd
        then
                finger $user_name
        fi
        done
then
        finger $user_name
        exit 0



fi

This is the error im getting

 ./project.sh: line 49: (myusernameisherebutimhidingit): command not found

Don't hide it, fix it. I don't know what if $user_name is supposed to do, but if you want to say "if $user_name is non-empty" you should use if [ -n "$user_name" ]. — that other guy
– that other guy, Commented Apr 12, 2016 at 23:40

zetavolt · Accepted Answer · 2016-04-12 23:27:35Z

1

The problem is that you are trying to run the command $user_name at several places, you probably want to replace $user_name with a check for the value of user name.

answered Apr 12, 2016 at 23:27

zetavolt

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2 Comments

ergology Over a year ago

what do u mean im new to this?

Gordon Davisson Over a year ago

@ergology: $user_name && "exit" 2> /dev/null does not make any sense at all. Without knowing what it's supposed to do, it's hard to tell you how to do it correctly.

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