I want to remove (only one) element by value from my array.
example :
x = [1,2,3,2]
x.remove(2)
result: x= [1,3]
But, i want to get [1,3,2].
thanks
3 Answers
As @7urkm3n mentioned in the comments, you can use x.delete_at to delete the first occurance
x.delete_at(x.index 2)
> x = [1,2,3,2]
=> [1, 2, 3, 2]
> x.delete_at(x.index 2)
=> 2
> x
=> [1, 3, 2]
1 Comment
stecb
I was thinking about perf of delete_at Vs. slice! ... they should be ~ the same.
You can use slice!(index, 1). You can get the 1st index of the element you want to delete by using index(element)
In your case you just have to do: x.slice!(x.index(2), 1) (or, as already mentioned, delete_at just providing the index)
Comments
You could write
x = [1,2,3,2]
x.difference([2])
#=> [1, 3, 2]
where Array#difference is as I've defined it my answer here. Because of the wide potential application of the method I've proposed it be added to the Ruby core.
Suppose
x = [1,2,3,2,1,2,4,2]
and you wished to remove the first 1, the first two 2's and the 4. To do that you would write
x.difference([1,2,2,4])
#=> [3, 1, 2, 2]
Note that
x.difference([1,2,2,4,4,5])
#=> [3, 1, 2, 2]
gives the same result.
To remove the last 1, the last two 2s and and the 4, write
x.reverse.difference([1,2,2,4]).reverse
#=> [1, 2, 3, 2]
1do u want to remove specific number or first number of array ?.delete_at(index of array)for that, or u can keep uniq like from[1,2,3,4,1]to make to make it[1,2,3,4]. just callx.uniq.