angular find substring in array

Question

I have an array like this in angular

app.myStringArray=
    [   'abcdefg',
        '123456',
        'qwerty'
    ];

Currently I have a common method that checks for value being in array like this

app.factory('commons', function () {


    var commons= {};

    //Checks if the current url is 
    commons.checkString= function (str) {

        if (app.myStringArray.indexOf(str) > -1) {
            return true; //current string is in list
        } else {
            return false;
        }
    }

    return commons;
}
);

This works if I send in the full string 'abcdefg' or '123456' or 'qwerty'.

How can I make it work even if I get part of the string like for eg: 'bcd' ?

a better oliver · Accepted Answer · 2016-04-18 07:50:47Z

3

To check if a string contains another one you can use String.indexOf() or as of ES6 String.includes().

To check if at least one item in an array matches a predicate you can use Array.some() or simply iterate over the array yourself.

ES6 solution:

function checkString(str) {    
  return myStringArray.some(s => s.includes(str));
}

ES5 solution:

function checkString2(str) {    
  return myStringArray.some(function(s) {
    return s.indexOf(str) > -1;
  });
}

answered Apr 18, 2016 at 7:50

a better oliver

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2 Comments

user20358 Over a year ago

shouldn't it be str.indexOf(s) > -1 ?

a better oliver Over a year ago

@user20358 Not if you want to test if "abcdefg" (=s) contains "bcd" (=str).

Jaydo · Accepted Answer · 2016-04-18 04:55:33Z

1

Iterate through the array and check indexOf(str) for each string in the array. No need for Angular.

var array = ['abcdefg', '123456', 'qwerty'];

function checkString(str) {
  
  for (var i = 0; i < array.length; i++) {
    if (array[i].indexOf(str) > -1) {
      return true;  
    }
  }
  
  return false;
}

alert(checkString("bcd"));

answered Apr 18, 2016 at 4:55

Jaydo

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