django-python create Multidimensional Array in views.py

Question

In models.py:

class PUser(models.Model):
        phone = models.TextField(blank=True, null=True)
        email = models.TextField()
        txt = models.TextField(blank=True, null=True)

I want to create Multidimensional Array for that.

For now this is what I have in the function in views.py:

def main(request):
    users = []
    for i in range (5):
        for a in range(3):
            users[i][a] = PUser.objects.all()
return render(request, 'main.html', {'users': users})

But I know its not correct, its not working.

How should I edit it?

And how the code in the main.html should be?

I was thinking about something like {{ users[2][3] }} for example. How the code should be? (I have read same questions but was not helpful for me)

Louis Barranqueiro · Accepted Answer · 2016-04-18 12:39:31Z

3

Since PUser.objects.all() returns an array of PUser object, you just have to write :

def main(request):
    users = PUsers.objects.all()
    return render(request, 'main.html', {'users': users})

and in your template, iterate on users array :

{% for user in users %}
    {{ user.phone }}
    {{ user.email }}
    {{ user.txt }}
{% endfor %}

If you wanna print a specific user, you can by specifying its index :

{{ users[3].phone }}
{{ users[3].email }}
{{ users[3].txt }}
# or
{{ users.3.phone }}
{{ users.3.email }}
{{ users.3.txt }}

edited Apr 18, 2016 at 12:39

answered Apr 18, 2016 at 8:48

Louis Barranqueiro

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7 Comments

niloofar Over a year ago

But as I noticed I want to use something like {{ users[2][3] }}. I want to choose the index I want and put it in different places in my file code. I dont want to print all of them one after an other in a certain place, so dont want to use "for loop". I want to be able to select which index be printed in which place in the code.

Louis Barranqueiro Over a year ago

I add an example to print a specific user :)

niloofar Over a year ago

By using {{ users[3].phone }} I faced with this error: Could not parse the remainder: '[3].phone' from 'user[3].phone'

Louis Barranqueiro Over a year ago

use users[3] variable and not user[3]

Louis Barranqueiro Over a year ago

try with users.3.phone, do you use django template or jinja?

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