Sort array based on another array

Question

I want to sort the second array($array2) based on first array($field['choices'])

$field_name = "field_52f8fcdd21cb6";
$field = get_field_object($field_name);

foreach( $field['choices'] as $k=>$v) {
    echo $k."==".$v."<br>";
}

The above code gives me the following output

Gyana Yagna==Gyana Yagna
Festival==Festival
Retreat==Retreat
Performance==Performance
Swaranjali==Swaranjali

Now the second array starts

echo "<br><br><br>";
$array2 = array("Gyana Yagna","Gyana Yagna","Gyana Yagna","Retreat","Festival","Festival");

foreach( $array2 as $k=>$v)
{
    if(in_array($v,$field['choices']))
    {
        echo $array2[$k]."<br>";
    }
    else
    {
        echo $array2[$k+1]."<br>";
    }
}

Desired output should be

Gyana Yagna
Gyana Yagna
Gyana Yagna
Festival
Festival
Retreat

Whereas I am getting the following output

Gyana Yagna
Gyana Yagna
Gyana Yagna
Retreat
Festival
Festival

Any help is highly appreciated. Thanks in advance.

Output is wrong because you are looping over the 2nd array hence $array2[3], is returning $v = "Retreat" which is then used by in_array($v,$field['choices']) function. — Abbasi
– Abbasi, Commented Apr 18, 2016 at 22:25

Abbasi · Accepted Answer · 2016-04-18 23:05:13Z

1

Here is a solution based on my comment:

$field['choices']= array('Gyana Yagna', 'Festival', 'Retreat');


echo "<br><br><br>";
$array2 = array("Gyana Yagna","Gyana Yagna","Gyana Yagna","Retreat","Festival","Festival");

foreach( $field['choices'] as $k=>$v)
{
foreach($array2 as $k2=>$v2){
    if($v==$v2)
      {
          echo $array2[$k2]."<br>";
      }
}

}

And Output is same as your desired output.

answered Apr 18, 2016 at 23:05

Abbasi

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