laravel undefined variable, array_where

Question

private function delete_read($id)
{
    $unread = unserialize(Auth::user()->unread);

    if (in_array($id, $unread))
    {
        $new = array_where($unread, function ($key, $value) {
            return $value != $id;
        });

        dd($new);
    }


}

I'm trying to delete read post from an unread posts list. The above codes give me an Undefined variable: id error, which refers to this line of code: return $value != $id;

So my question is how to pass variables into array_where method?

BTW, is there any better way to delete given elements from an array, other than unset? Or would unset be better than my array_where approach?

Thanks.

Tim Biegeleisen · Accepted Answer · 2016-04-19 00:47:30Z

2

Because $id was defined outside of the callback function you pass into array_where() this variable is out of scope and won't be available by default. However, you can try the use keyword to force $id to be in scope:

if (in_array($id, $unread))
{
    $new = array_where($unread, function ($key, $value) use ($id) {
        return $value != $id;
    });

    dd($new);
}

answered Apr 19, 2016 at 0:47

Tim Biegeleisen

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