how to open a file using exec method in java?

Question

C:\Users\Admin\Downloads\VID_20160226_203631957.mp4

when I execute above line in command prompt the corresponding video gets played with default media player.

But when I try to do same using java Runtime class it doesnt work. I am using following method.

Runtime r= Runtime.getRuntime();
r.exec("C:\Users\Admin\Downloads\VID_20160226_203631957.mp4")

in Windows try to use command start C:\Users\Admin\Downloads\VID_20160226_203631957.mp4. If filename contains spaces use double quotes for your file path. For example: if your file name is my file.mp4 then use the command: start "my file.mp4" — user784540
– user784540, Commented Apr 19, 2016 at 3:34
Do not use runtime exec. Use Process Builder docs.oracle.com/javase/8/docs/api/java/lang/ProcessBuilder.html — Hector
– Hector, Commented Apr 19, 2016 at 3:36
@Hector You should create an answer for that. It's the correct solution. — ManoDestra
– ManoDestra, Commented Apr 19, 2016 at 3:50

Elliott Frisch · Accepted Answer · 2016-04-19 04:02:36Z

3

Use Desktop.open(File) which launches the associated application to open the file. Something like,

File f = new File("C:/Users/Admin/Downloads/VID_20160226_203631957.mp4");
try {
    Desktop.getDesktop().open(f);
} catch (IOException e) {
    e.printStackTrace();
}

You might prefer to build the path relative to the user's home directory; something like

File downloads = new File(System.getProperty("user.home"), "Downloads");
File f = new File(downloads, "VID_20160226_203631957.mp4");

edited Apr 19, 2016 at 4:02

answered Apr 19, 2016 at 3:38

Elliott Frisch

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Comments

user4910279 · Accepted Answer · 2016-04-19 03:45:57Z

1

Try this.

Runtime r= Runtime.getRuntime();
r.exec("cmd /c C:\\Users\\Admin\\Downloads\\VID_20160226_203631957.mp4");

answered Apr 19, 2016 at 3:45

user4910279

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