php class function as parameter with $this->

Question

I have a webservice class with a number of private functions. I have a main function which decides which function to call according to the first parameter of the web service call.

$actions = [
        "CHECK_LOGIN"     => "checkLogin" 
    ,   "CHECK_FB"        => "checkFB"  
    ,   "GET_DETAILS"     => "getDetails" 
    ,   "SAVE_DETAILS"    => "saveDetails" 
    ,   "CHANGE_PWD"      => "saveDetails" 
    ,   "SEND_ECODE"      => "sendEmailCode"
]

So, its easy to find which function to call according to the parameter passed:

if (!array_key_exists($action, $actions))
  $rep = ["status" => STATUS_ERROR, "errMsg" => "Action '$action' unknown"];
else {
   $method = $actions[$action];
   $rep = $method($req);
}

My problem is that I can't call "$method" what ever it is (e.g. "checkFB"), I need to call $this->method (i.e. "$this->checkFB") How do I put the $this-> in front of the function name found in the $actions array??

I was trying to call "$this->method", but what I needed was "$this->$method" !!! — Francesco
– Francesco, Commented Apr 19, 2016 at 9:46
Possible duplicate of PHP Call a instance method with call_user_func within the same class — Aurel
– Aurel, Commented Apr 19, 2016 at 9:48

user6067756 · Accepted Answer · 2016-04-19 12:12:11Z

1

You can do it like this:

if (!array_key_exists($action, $actions))
  $rep = ["status" => STATUS_ERROR, "errMsg" => "Action '$action' unknown"];
else {
   $method = $actions[$action];
   $rep = $this->$method($req);
}

answered Apr 19, 2016 at 12:12

user6067756

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