Querying a REST API with a string parameter using Angular Resource

Question

I am trying to query a REST API which I have hosted locally and this should work something as follows:

http://localhost:51608/api/[email protected]

That request works and it returns a User Object with an AccessLevel property. Now I have an angular application and want to query that URL using Angular Resource. I have something as follows but the URL is not being built properly.

(function () {
    "use strict";

    angular
        .module("common.services")
        .factory("userRoleResource",
                ["$resource",
                 "appSettings",
                    userRoleResource])

    function userRoleResource($resource, appSettings) {
        return $resource(appSettings.serverPath + "/api/UserRole:email", { email: '@email'});
    }
})();

I am querying the above as follows:

userRoleResource.query({ email: vm.userData.email },
   function (data) {
      vm.userData.accessLevel = data.AccessLevel;
});

But this is generating the request as follows:

http://localhost:51608/api/[email protected] instead of http://localhost:51608/api/UserRole?email:[email protected]

What's wrong here?

function userRoleResource($resource, appSettings) { return $resource(appSettings.serverPath + "/api/UserRole?email=:email", { email: '@email'}); } — thegio
– thegio, Commented Apr 19, 2016 at 14:53

Pankaj Parkar · Accepted Answer · 2016-04-19 14:58:24Z

1

As per $resource current working it does replace :email with the email parameter you provided to $resource object. You can have encoded : in a place like %3A

function userRoleResource($resource, appSettings) {
    return $resource(appSettings.serverPath + "/api/UserRole%3A:email", { email: '@email'});
}

answered Apr 19, 2016 at 14:58

Pankaj Parkar

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Comments

Bameza · Accepted Answer · 2016-04-19 15:00:14Z

0

Why don't you just format your string like :

return $resource(appSettings.serverPath + "/api/UserRole?email:" + email});

answered Apr 19, 2016 at 15:00

Bameza

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1 Comment

Pankaj Parkar Over a year ago

Are you considering to create $resource object each time when you call method? I don't think so that would be an good idea to go..

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