Ruby: How to execute only one if condition in a loop?

Question

I am trying to only have one of the if conditions to print.

subnet = ['10.14.1.32/27', '10.17.8.2/29']
system = gets.chomp
subnet.each do |cidr|
  address_space = NetAddr::CIDR.create(cidr)
  if address_space.contains? system
    puts "found"
  else
    puts "not found"
  end
end

the output I get for something like 10.17.8.3 would be

not found
found

How would I only get one response? I tried using breaks but that doesn't work. Thanks All!

Your code outputs one OR the other for each element of subnet. Not sure what you expect — Petr Gazarov
– Petr Gazarov, Commented Apr 19, 2016 at 19:58
BTW, in order to help your readers understand your intent, collections should have plural names, so 'subnet' should be 'subnets'. — Keith Bennett
– Keith Bennett, Commented Apr 20, 2016 at 14:55

tadman · Accepted Answer · 2016-04-19 20:08:41Z

5

The trick is to use the Enumerable#find method:

subnet = ['10.14.1.32/27', '10.17.8.2/29'].collect do |cidr|
  NetAddr::CIDR.create(cidr)
end

system = gets.chomp

found = subnet.find do |cidr|
  cidr.contains?(system)
end

if (found)
  puts "found"
else
  puts "not found"
end

That will return either the CIDR object that matched or nil if nothing did.

edited Apr 19, 2016 at 20:08

answered Apr 19, 2016 at 20:00

tadman

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Comments

Nguyen Ruby · Accepted Answer · 2016-04-20 03:38:48Z

0

subnet is an array and your code using each loop. So if subnet is more than 1 elements it will return subnet.count result. I do not know what exactly did you want. But if you want to break of loop in this case, you can using return

answered Apr 20, 2016 at 3:38

Nguyen Ruby

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