Filter array for creating menu sub menu in php

Question

My existing array like this

$menus = array(
        0 =>array(
                "id"=> 1,
                "name"=> "A",
                "parent_id"=> 0
            ),
         1 =>array(
                "id"=> 2,
                "name"=> "B",
                "parent_id"=> 1
            ),
         2 =>array(
                "id"=> 3,
                "name"=> "C",
                "parent_id"=> 1
            ),
         3 =>array(
                "id"=> 4,
                "name"=> "D",
                "parent_id"=> 2
            ),
        4 =>array(
                "id"=> 5,
                "name"=> "E",
                "parent_id"=> 0
            ),

     );

I want to create that array like below output.

Expected Array

Array
(
    [0] => Array
        (
            [Menu] => Array
                (
                   [0] => Array
                          ( [name] => A
                            [Sub_menu] => Array
                             (
                                  [0] => Array
                                      (
                                        [name] => B
                                      ),
                                  [1] => Array
                                     (
                                        [name] => C
                                        [Sub_menu] => Array
                                          (
                                              [0] => Array
                                              (
                                                [name] => D
                                              ),

                                          )
                                     )
                             )
                          ),
                   [1] => Array
                          ( [name] => E

                          )
                )
         )
)

I tried some code and those are not working . my work output was like this image

which repeating again in foreach loop in menu.

Great that you want to achieve that. but what about your effort? show us what you have tried so for? — Death-is-the-real-truth
– Death-is-the-real-truth, Commented Apr 20, 2016 at 4:39
@Anant i placed my php code though there some different because I worked on MVC platform. — Lemon Kazi
– Lemon Kazi, Commented Apr 20, 2016 at 4:47

Andrew · Accepted Answer · 2016-04-20 05:20:24Z

3

You can use this function to construct menu recursively.

function makeMenu($items, $parentId)
{
    $menu = array_filter($items, function ($item) use ($parentId) {
        return $item['parent_id'] == $parentId;
    });
    foreach ($menu as &$item) {
        $subItems = makeMenu($items, $item['id']);
        if (!empty($subItems)) {
            $item['sub_menu'] = $subItems;
        }
    }
    return $menu;
}

Call it with $parentId = 0 and it will do work.

$readyMenu = makeMenu($itemsArray, 0);

edited Apr 20, 2016 at 5:20

answered Apr 20, 2016 at 5:05

Andrew

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Comments

Manjeet Barnala · Accepted Answer · 2016-04-20 04:48:02Z

0

This code will work for you, Try...

$all = array(
        0 =>array(
                "id"=> 1,
                "name"=> "A",
                "parent_id"=> 0
            ),
         1 =>array(
                "id"=> 2,
                "name"=> "B",
                "parent_id"=> 1
            ),
         2 =>array(
                "id"=> 3,
                "name"=> "C",
                "parent_id"=> 1
            ),
         3 =>array(
                "id"=> 4,
                "name"=> "D",
                "parent_id"=> 2
            ),
        4 =>array(
                "id"=> 5,
                "name"=> "E",
                "parent_id"=> 0
            ),
    );  

foreach($all as $key => $val)
{
    if($val['parent_id']==0)
    {
        $data[]=$val;

        foreach($all as $k => $v)
        { 
            if($val['id'] == $v['parent_id']){
                $data[$key]['sub_menu'][]= $v;
                foreach($all as $a => $s)
                { 
                    if($v['id'] == $s['parent_id']){
                        $data[$key]['sub_menu'][$key]['sub_menu'][]= $s;
                    }
                }
            }
        }
    }
}
echo "<pre>"; print_r($data);
?

This will output like this :

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => A
            [parent_id] => 0
            [sub_menu] => Array
                (
                    [0] => Array
                        (
                            [id] => 2
                            [name] => B
                            [parent_id] => 1
                            [sub_menu] => Array
                                (
                                    [0] => Array
                                        (
                                            [id] => 4
                                            [name] => D
                                            [parent_id] => 2
                                        )

                                )

                        )

                    [1] => Array
                        (
                            [id] => 3
                            [name] => C
                            [parent_id] => 1
                        )

                )

        )

    [1] => Array
        (
            [id] => 5
            [name] => E
            [parent_id] => 0
        )

)

answered Apr 20, 2016 at 4:48

Manjeet Barnala

2,9951 gold badge13 silver badges21 bronze badges

4 Comments

Manjeet Barnala Over a year ago

look you have changed array name to $All, it is $all everywhere in my code...

Manjeet Barnala Over a year ago

thats why it shows the warning Invalid argument supplied for foreach(), change $All to $all

Manjeet Barnala Over a year ago

Thiis is working perfectly @LemonKazi https://eval.in/556636

Death-is-the-real-truth Over a year ago

@ManjeetBarnala although your code works, but i suggest both you and OP to look andrew answer. Accurate+fast without any limitations.Thanks.

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