Python validation error object is not json serializable

Question

I have an exception which gives me error from form like::

except ValidationError as e:
    return JsonResponse(e, safe=False)

It is giveing me the error ValidationError({'age': [u'This field is required.'], 'name': [u'This field is required.']}) is not JSON serializable

Why I am getting this error and how can I make it work .. Any idea ??

If you're using a form then why not let the form handle the validation as normal? Please try to show a minimal reproducible example — Sayse
– Sayse, Commented Apr 21, 2016 at 10:28
@Sayse I am posting the from form ajax so I want to send the error as response.. — gamer
– gamer, Commented Apr 21, 2016 at 10:38
Don't know why you @ -ed me. But still, Sayse's point is still valid; the form collects the validation errors into an error list, and it's that that you should be serializing. Don't return responses from inside form methods, in any case. — Daniel Roseman
– Daniel Roseman, Commented Apr 21, 2016 at 10:40
Yes it is giving me validatation errors in list but it is not being serialized. How come ? — gamer
– gamer, Commented Apr 21, 2016 at 10:45

Selcuk · Accepted Answer · 2016-04-21 10:55:21Z

3

Your e is an instance of ValidationError, not a dict. In order to access the message details you can use the .message_dict property:

return JsonResponse(e.message_dict, safe=False)

edited Apr 21, 2016 at 10:55

answered Apr 21, 2016 at 10:52

Selcuk

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3 Comments

gamer Over a year ago

It is giving me error dict object is not callable

gamer Over a year ago

thanks man.. worked like a charm.. one question.. I have tried this too # response = serializers.serialize('json', e) return JsonResponse(response, safe=False) and why it didn't worked. It is supposed to serialize this right ?

Selcuk Over a year ago

Again, your e variable is not serializable. So no, this is normal behavior.

Despota · Accepted Answer · 2020-04-03 15:26:53Z

1

You can use this

https://docs.djangoproject.com/en/2.0/ref/forms/api/#django.forms.Form.errors.as_json

as simple as:

except ValidationError as e:
  return e.as_json

answered Apr 3, 2020 at 15:26

Despota

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Comments

Mylyanyk Marko · Accepted Answer · 2023-11-21 23:56:28Z

0

For me given answers didn't work. I've solved it by using ValidationError method get_full_details().

except ValidationError as e:
    return JsonResponse(e.get_full_details(), safe=False)

answered Nov 21, 2023 at 23:56

Mylyanyk Marko

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