PHP Regular expression to extract data from a url source

Question

URL: somedoamin.com/r?ammem/hlaw:@field(DOCID+@lit(hj0011))

How can I extract the didit after hj, that is 001;

The format will always be @lit(hj<integer>))

Please help

I tried regular expression

\s+(lit)\d+

Lucas Araujo · Accepted Answer · 2016-04-21 12:46:17Z

3

Try this regex:

@lit\(hj(\d+)\)\)

See the demo below.

Regex Demo

answered Apr 21, 2016 at 12:46

Lucas Araujo

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Comments

Aaron · Accepted Answer · 2016-04-21 12:53:05Z

0

I would use the following :

(?<=@lit\(hj)\d*

It uses a positive look-behind to check for preceding @lit(hj and captures every digit up to the next closing parenthesis.

Try it here!

An alternative that captures anything up to the next parenthesis :

(?<=@lit\(hj)[^)]*

edited Apr 21, 2016 at 12:53

answered Apr 21, 2016 at 12:45

Aaron

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5 Comments

Wiktor Stribiżew Over a year ago

Watch out, this will match any characters, not just digits.

Aaron Over a year ago

Indeed, added a digit-only alternative.

Nabeel Khan Over a year ago

this one is uselessly too slow due to lookbehind. the one posted by ibarros is better imho

Nabeel Khan Over a year ago

plus he said " integer" not "anything other than )" so again a useless [^)] that will check all characters not just the integers.

Aaron Over a year ago

Ok I switched the main code and its alternative. You're right about the slowness, but some people will prefer having the whole logic implemented in the regex rather than having to select a specific group afterwards

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