Something like doesn't work, what's the work around?
var tgtCol = $('td[aria-describedby=tblGrid_Subject]');
var tgtHdr = $('#tblGrid_Subject');
$(tgtHdr, tgtCol).attr('colSpan', '3');
-
Bennor has got the best answer.. I'll accept once I can (10 mins)bcm– bcm2010-09-10 02:29:24 +00:00Commented Sep 10, 2010 at 2:29
-
The point of putting them in a variable is because I'm using the targets more than once.bcm– bcm2010-09-10 02:30:23 +00:00Commented Sep 10, 2010 at 2:30
Add a comment
|
5 Answers
var tgtCol = $('td[aria-describedby=tblGrid_Subject]');
var tgtHdr = $('#tblGrid_Subject');
$(tgtHdr).add(tgtCol).attr('colSpan', '3');
This will also work:
var stuff = $('td[aria-describedby=tblGrid_Subject], #tblGrid_Subject');
stuff.attr('colSpan', '3');
1 Comment
Chris Harrison
+1 because it actually answers the question about selecting multiple OBJECTS.
You're close, you may combine multiple selectors with a comma, like so:
$('td[aria-describedby=tblGrid_Subject], #tblGrid_Subject').attr('colSpan', '3');
1 Comment
Chris Harrison
Not if you already have multiple objects and you don't know what events lead up to those objects being created.
As the first two lines already return a jQuery object, you can just do it like this:
tgtHdr.attr('colSpan', '3');
tgtCol.attr('colSpan', '3');
Comments
You can use a multiple selector initially:
$('td[aria-describedby=tblGrid_Subject], #tblGrid_Subject').attr('colSpan', '3');
Comments
If it's two selectors, you can use 'merge', but if it's more than two you should use 'each'
// using merge:
$.merge(selector1, selector2) // the rest
// using each:
$([selector1, selector2, selector3, .....etc]).each(function(){
// your code here
});
