PHP Array Echo Not Working

Question

I have an array like:

[meta] => Array (
  [company] => Company, LLC
  [confirmation] => 6391381
  [reference] => None
  [service] => Service
  [timestamp] => 2016-04-25 11:12:54
  [user] => company
)
[result] => Array (
  [action] => REVIEW
  [detail] => TRANSACTION REQUIRES FURTHER ATTENTION
  [issues] => Array (
      [0] => DOB CHECK FAILED
    )
)
[output] =>  Array ( )

I am attempting to echo the 'action' value like this:

$json_result = json_decode($result, true); 
echo "$json_result[result]['action']";

But instead of getting 'REVIEW' I am getting: 'Array['action']'

Any thoughts?

@jon when i try it like this i get the following error: Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING) — Tom Canfarotta
– Tom Canfarotta, Commented Apr 25, 2016 at 15:23
The code example I gave would not produce that error, or any error assuming your question is accurate. You've used it wrong. — Jonnix
– Jonnix, Commented Apr 25, 2016 at 15:24
Yes it would (if still in double quotes). The single quoted array key inside the double quoted string is wrong. php.net/manual/en/… To use quoted keys inside double quotes, it must be {} enclosed. — Michael Berkowski
– Michael Berkowski, Commented Apr 25, 2016 at 15:27
@MichaelBerkowski Do you see any double quotes in my comment? — Jonnix
– Jonnix, Commented Apr 25, 2016 at 15:28

serakfalcon · Accepted Answer · 2016-04-25 15:26:37Z

2

using arrays inside strings leads to madness. or at least horrible frustration.

as Jon Stirling pointed out, in your case why even bother putting the variable in a double quote?

echo $json_result['result']['action'];

works just fine. If you must use an array inside a string, escape it with curly braces

echo "{$json_result['result']['action']}";

answered Apr 25, 2016 at 15:26

serakfalcon

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Comments

Gergely Lukacsy · Accepted Answer · 2016-04-25 15:46:14Z

1

You're missing the apostrophes from the first index:

$json_result[result]['action'];

It should look like this:

$json_result['result']['action'];
             ^      ^

Edit: You can use regular php syntax to address array values if you put the whole expression between curly braces ( { ):

echo "This is the result: {$json_result['result']['action']};"

...or simply remove the double quotes (") from echo.

More info here: php echo

edited Apr 25, 2016 at 15:46

answered Apr 25, 2016 at 15:26

Gergely Lukacsy

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Comments

WhSol · Accepted Answer · 2016-04-25 15:22:36Z

0

To review all array

print_r($json_result);

To view only action

echo $json_result['result']['action'];

answered Apr 25, 2016 at 15:22

WhSol

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2 Comments

Tom Canfarotta Over a year ago

When i try it like this I get the following error: Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING)

Michael Berkowski Over a year ago

@TomCanfarotta If you're getting the T_ENCAPSED AND WHITESPACE is't sbecause you still have double quotes surrounding the whole thing as echo "$json_result['result']['action']"; Note the example above does not have them.

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