C++ for loop using an array

Question

I know this is a basic question, but I'm a Python user very new to C++

I need to compute a function (cosmology.bias_eff) using a for loop for which the input parameter (Mass_min) needs to be multiplied by an array (M_ratio).

I am making a mistake here by using two for loops.

vector<double> M_ratio = {1.0,0.9,1.1,1.05,1.1,1.15,1.2,1.25,1.2};
double Mass_min = 2e13;
double Delta0 = 200.0;

for (redshift=0.0;redshift<1.7;redshift=redshift+0.2)
{   
    for (size_t i=0; i<M_ratio.size(); i++)
    {
        double Delta = cosmology.DeltaR(Delta0, redshift);

        double bias_eff = cosmology.bias_eff(M_ratio[i]*Mass_min,redshift,Delta);

        cout << bias_eff <<"," << endl;
    }
}

What I want is, for each redshift in the for loop, I want Mass_min to be multiplied by M_ratio,

i.e. for redshift = 0.0, Mass_min = Mass_min*1.0, for redshift = 0.2, Mass_min = 0.9*Mass_min and so on.

Jean-Baptiste Yunès · Accepted Answer · 2016-04-28 13:27:49Z

7

You need only a single loop:

vector<double> M_ratio = {1.0,0.9,1.1,1.05,1.1,1.15,1.2,1.25,1.2};
double redshift;
int i;
for (redshift=0.0,i=0; i<M_ratio.size(); i++,redshift+=0.2) {
  double Delta = cosmology.DeltaR(Delta0, redshift);
  double bias_eff = cosmology.bias_eff(M_ratio[i]*Mass_min,redshift,Delta);
  cout << bias_eff <<"," << endl;
}

On each iteration, redshift in incremented by 0.2, at the same time i is incremented by one. Inside the loop the needed computation takes place.

edited Apr 28, 2016 at 13:27

answered Apr 28, 2016 at 13:22

Jean-Baptiste Yunès

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1 Comment

user3397243 Over a year ago

but shouldn't it be for (double redshift = 0.0, i=0;) instead of int ?

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