package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.Replace("golang", "g", "1", -1))
}
How to replace all characters in string "golang" (above string) by * that is it should look like "******"?
2 Answers
By replacing all characters you would get a string with the same character count, but all being '*'. So simply construct a string with the same character-length but all being '*'. strings.Repeat() can repeat a string (by concatenating it):
ss := []string{"golang", "pi", "世界"}
for _, s := range ss {
fmt.Println(s, strings.Repeat("*", utf8.RuneCountInString(s)))
}
Output (try it on the Go Playground):
golang ******
pi **
世界 **
Note that len(s) gives you the length of the UTF-8 encoding form as this is how Go stores strings in memory. You can get the number of characters using utf8.RuneCountInString().
For example the following line:
fmt.Println(len("世界"), utf8.RuneCountInString("世界")) // Prints 6 2
prints 6 2 as the string "世界" requires 6 bytes to encode (in UTF-8), but it has only 2 characters.
1 Comment
photoionized
Good call on the multibyte characters.
A simple way of doing it without something like a regex:
https://play.golang.org/p/B3c9Ket9fp
package main
import (
"fmt"
"strings"
)
func main() {
fmt.Println(strings.Repeat("*", utf8.RuneCountInString("golang")))
}
Something more along the lines of what you were probably initially thinking:
https://play.golang.org/p/nbNNFJApPp
package main
import (
"fmt"
"regexp"
)
func main() {
re := regexp.MustCompile(".")
fmt.Println(re.ReplaceAllString("golang", "*"))
}
1 Comment
Peter Yeremenko
Seems the answer of icza should be set as accepted because it takes into account that string may have multibyte runes
strings.Replace("golang", "golang", "******", -1)?