Fill A Variable Size Array

Question

int* HT;
int HTc = 500;
HT = new int[HTc] = {-1}; //Fill array with -1

I get the warning:

extended initializer lists only available with -std=c++0x or =std=gnu++0x

I'll assume this means it isn't compatible with the ANSI standard, which my prof. is nuts for. How else would I do this though?

Seriously, stop what you're doing and make your own vector and string class. Then just use std::fill over it. (Or if your professor is stupid in that regard as well, make your own fill.) — GManNickG
– GManNickG, Commented Sep 12, 2010 at 5:44
I wouldn't recommend that you use variable length arrays. EDIT: Oh, you are using dynamic memory. — Alexander Rafferty
– Alexander Rafferty, Commented Sep 12, 2010 at 9:54

Todd Gardner · Accepted Answer · 2010-09-12 05:44:19Z

6

Use std::fill. It would be better to use a std::vector than a c style array, but just for demonstration:

#include <algorithm>

int HTc = 500;
int HT[] = new int[HTc];
std::fill(HT, HT+HTc, -1);
// ...
delete[] HT;

answered Sep 12, 2010 at 5:44

Todd Gardner

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Mark Ransom · Accepted Answer · 2010-09-12 05:43:22Z

2

I'm not sure this would work the way you want even if you used the recommended options - wouldn't it initialize the first array element to -1 and the rest to 0?

Just loop through all the elements and set them individually.

answered Sep 12, 2010 at 5:43

Mark Ransom

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Jerry Coffin · Accepted Answer · 2010-09-12 07:13:50Z

2

Unless you have some truly outstanding reason to do otherwise, the preferred method would be to not only use a vector, but also specify the initial value when you invoke the ctor: std::vector<int> HT(500, -1);

answered Sep 12, 2010 at 7:13

Jerry Coffin

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2 Comments

GManNickG Over a year ago

His professor doesn't allow it, apparently. How do terrible programmers end up teaching?

Jerry Coffin Over a year ago

I guess it fits the old line about "those who can, do; those who can't, teach; those who can't teach, teach PE" -- only in this case, they apparently teach programming. Which, in turn, brings to mind another old line, to the effect that: "Free verse is the most difficult poetry to write acceptably -- and therefore the most often attempted by those who cannot write any poetry acceptably."

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