Split list returned from urlparse in python

Question

I am able to parse url using urlsplit and get parameters using query argument.

url is '/api/v1/test?par1=val1&par2=val2a%3D1%26val2b%3Dfoo%26val2c%3Dbar'

After using urlsplit and query I get

'par1=val1&par2=val2a%3D1%26val2b%3Dfoo%26val2c%3Dbar'

And after running parse_qs on above I get

{'par2': ['val2a=1&val2b=foo&val2c=bar'], 'par1': ['val1']}

Here is output which is exactly what I need

'par1': ['val1']

I get return as list for one of parameter which has decoded data as below

'par2': ['val2a=1&val2b=foo&val2c=bar]

I can split par2 using split method at & and = and get val2a...

But is there any better way for this?

Please add the url which you are parsing as well.

AKS
– AKS

2016-04-29 17:47:22 +00:00
Commented Apr 29, 2016 at 17:47 — AKS
– AKS, Commented Apr 29, 2016 at 17:47
@AKS updated with url

user2661518
– user2661518

2016-04-29 17:56:39 +00:00
Commented Apr 29, 2016 at 17:56 — user2661518
– user2661518, Commented Apr 29, 2016 at 17:56
Please check my answer.

AKS
– AKS

2016-04-29 18:10:54 +00:00
Commented Apr 29, 2016 at 18:10 — AKS
– AKS, Commented Apr 29, 2016 at 18:10

AKS · Accepted Answer · 2016-04-29 18:03:53Z

2

You can again use parse_qs on the value of par2

>>> url = '/api/v1/test?par1=val1&par2=val2a%3D1%26val2b%3Dfoo%26val2c%3Dbar'
>>> q = parse_qs(urlparse(url).query)
>>> q
{'par2': ['val2a=1&val2b=foo&val2c=bar'], 'par1': ['val1']}
>>> parse_qs(q['par2'][0])
{'val2b': ['foo'], 'val2c': ['bar'], 'val2a': ['1']}

After the last result you can get the value of val2a etc.

answered Apr 29, 2016 at 18:03

AKS

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Comments

Bharel · Accepted Answer · 2016-04-29 18:20:00Z

1

split on & and partition on = is probably the easiest and most efficient way.

result = {k: v for k, _, v in (pair.partition('=') for pair in values.split('&'))}
# or
result = dict(pair.split('=') for pair in values.split('&'))

Using re.sub() is another option but I believe it's just over complicating stuff.

edited Apr 29, 2016 at 18:20

answered Apr 29, 2016 at 18:11

Bharel

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