PHP variable concatenation

Question

I'm trying to change a hardcoded variable value to dynamic, but can't seem to get the concatenation correct...

The hardcoded value is...

$token = "../wp-content/themes/mytheme/styles/test/sidebar";

And I'm trying to replace that with...

$token = ".get_bloginfo('template_directory')."styles/test/sidebar";

But its not working the same as when I hardcode the value.

What am I missing?

Here's the rest of the code (the imagegif function never fires with the dynamically generated variable...

$color = imagecolorallocate($img, $info["red"], $info["green"], $info["blue"]);
    for ($i = $startPixel-1; $i < $endPixel; $i++)
    {
        imagesetpixel($img, $i, 0, $color);
    }

    imagegif($img, $token.'.gif');
}

Fosco · Accepted Answer · 2010-09-13 14:41:04Z

1

$token = get_bloginfo('template_directory') . "styles/test/sidebar";

The . is the concatenation operator, so you wouldn't want the get_bloginfo() function inside of quotes. This assumes the function returns a string that ends in a /

answered Sep 13, 2010 at 14:41

Fosco

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1 Comment

Scott B Over a year ago

Thanks Fosco, I missed that. Also had to put a "/" in front of "styles".

Gazler · Accepted Answer · 2010-09-13 14:41:16Z

0

$token = get_bloginfo('template_directory')."styles/test/sidebar";

Is that what you mean? You had the function as a string instead of a function.

answered Sep 13, 2010 at 14:41

Gazler

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Comments

Daniel Vandersluis · Accepted Answer · 2010-09-13 14:41:52Z

0

From your code:

$token = ".get_bloginfo('template_directory')."styles/test/sidebar";

This line has a a stray quote and period at the beginning. You probably wanted to do:

$token = get_bloginfo('template_directory') . "styles/test/sidebar";

Function calls cannot be within strings, and the concatenation operator (.) must be outside of the string.

answered Sep 13, 2010 at 14:41

Daniel Vandersluis

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Comments

RobertPitt · Accepted Answer · 2010-09-13 14:41:58Z

0

Only strings should be wrapped within quotes.

$token = get_bloginfo('template_directory') . "styles/test/sidebar";

answered Sep 13, 2010 at 14:41

RobertPitt

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vindia · Accepted Answer · 2010-09-13 14:42:05Z

0

Your concatination is a bit off.

Try: $token = get_bloginfo('template_directory') . 'styles/test/sidebar';

answered Sep 13, 2010 at 14:42

vindia

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2 Comments

RobertPitt Over a year ago

"Your concatination is a bit off."... is that not the question ?

vindia Over a year ago

Maybe I meant his style of concatenating being a bit weird. But yeah, that was the question I guess ;-)

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