I have a string output from another program that shows the date as
16/05/03 # (YY/MM/DD)
and I wish to change it to
03/05/16 #(DD/MM/YY)
and here is how the date is supplied
(date = info[4].replace('"', '')
i have tried
dates = str(date)[::-1]
but that gave me an output of
40/50/61
not quite what I wanted
any ideas using a minimal code as possible?
>>> '/'.join('16/05/03'.split('/')[::-1])
'03/05/16'
or
>>> '/'.join(reversed('16/05/03'.split('/')))
'03/05/16'
or using datetime library:
>> from datetime import datetime
>>> datetime.strftime(datetime.strptime('16/05/03', '%y/%m/%d'), '%d/%m/%y')
'03/05/16'
Using datetime give you alot more control with changing the format to suite what you want.
import datetime
d = datetime.strptime('16/05/03', '%y/%m/%d')
print d.strftime('%d/%m/%y')
